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Slav-nsk [51]
3 years ago
6

What is detoxification?

Health
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

A) Gradual and complete withdrawal from a drug..

atroni [7]3 years ago
8 0
The answer you are looking for is letter A.
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Freezing-up or being unable to move or respond physically during a traumatic event is an example of
Charra [1.4K]

Answer:

shock

Explanation:

6 0
3 years ago
Read 2 more answers
John is a 15 year old young man who is struggling in school, smoking pot, and rebelling pretty strongly against his parents. He
kotegsom [21]

Answer: Despite his hatred towards his parents, I would definitely suggest to John that it would be probably a good idea to take some time out of your day and talk to his parents, let them know how he truly feels. Why? Because if he does, maybe his parents will realize the bad things they have done to make John feel the way he feels, and change the way they act.

Another suggestion that I would provide John would be to stay calm, and avoid anything negative. Why? If he does this, over-time, his depression would get better, instead of the negative things in his life making it worse.

Lastly, another suggestion I would provide John includes medical attention. Depression can’t be cured just with avoiding problems. You need to take medicine as well. So, what I would suggest is for John to go see a doctor who is familiar with depression, anxiety, and all that Jazz, so that the doctor can provide John a few medicines he should take daily.

5 0
3 years ago
If 2^x=3^y=12^z, show that 1÷z=1÷y+2÷x.....​
Ostrovityanka [42]

Answer:

Proof of \dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}  is shown below.

Explanation:

The given equation is

2^x=3^y=12^z

To prove : \dfrac{1}{z}=\dfrac{1}{y}+\dfrac{2}{x}

Proof : Let as assume,

2^x=3^y=12^z=k

2^x=k\Rightarrow 2=k^{\frac{1}{x}}    ...(1)

3^y=k\Rightarrow 3=k^{\frac{1}{y}}      ...(2)

12^z=k\Rightarrow 12=k^{\frac{1}{z}}    ...(3)

We know that

12=2\times 2\times 3

12=(2)^2\times 3

Using (1), (2) and (3), we get

k^{\frac{1}{z}}=(k^{\frac{1}{x}})^2\times k^{\frac{1}{y}}

k^{\frac{1}{z}}=k^{\frac{2}{x}}\times k^{\frac{1}{y}}

k^{\frac{1}{z}}=k^{\frac{2}{x}+\frac{1}{y}}

On comparing both sides, we get

\dfrac{1}{z}}=\dfrac{2}{x}+\dfrac{1}{y}

\dfrac{1}{z}}=\dfrac{1}{y}+\dfrac{2}{x}

Hence proved.

8 0
3 years ago
What is the sum for <br> 8 divided by 2 [2x2] =?
il63 [147K]
8 - 2(2*2)= 1 PEMDAS

First you have to do 2*2=4

Then,

4*2=8

Then,

8 divided by 8 is 1



3 0
3 years ago
When stress continues over long period of time, it is known as
Flauer [41]

Chronic or long term stress. Hope this was helpful!

7 0
3 years ago
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