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3 years ago

As the atoms of the Group 17 elements in the ground state are considered from top to bottom, each successive element has

Chemistry

2 answers:

Lelu [443]3 years ago

8 0

Answer: Option (1) is the correct answer.

Explanation:

As each element of group 17 has 7 valence electrons. Therefore, they tend to show same type of reactivity.

And, when they react with another element then they tend to show a change in their chemical composition.

As a result, we can say that elements of group 17 show similar chemical properties due to the presence of same number of valence electrons.

Thus, we can conclude that as the atoms of the Group 17 elements in the ground state are considered from top to bottom, each successive element has the same number of valence electrons and similar chemical properties.

VladimirAG [237]3 years ago

4 0

<span> elements in the same group have the same valence electrons. So it is either A or C. elements in the same group don't have identical chemical properties because the valence electrons are in different energy levels. So it should be A. same number of valence electrons and similar chemical properties.</span>

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Give the formula for the alkane containing 500 carbons.

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En un balneario necesitan calentarse 1 millón de litros de agua anuales, subiendo la temperatura desde 15 ºC a 50 ºC y para ello

MAXImum [283]

Answer:

a) $m_{CH_4}=2630kg$

b) 1657 €

Explanation:

Hola,

a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:

$Q_{H_2O}=m_{H_2O}Cp(T_2-T_1)=1x10^6LH_2O*\frac{1kgH_2O}{1LH_2O}*4.18\frac{kJ}{kg\°C}(50-15) \°C\\Q_{H_2O}=146.3x10^6kJ$

Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:

$Q_{H_2O}=-Q_{CH_4}=-146.3x10^5kJ=m_{CH_4}\Delta _cH_{CH_4}$

$m_{CH_4}= \frac{Q_{CH_4}}{\Delta _cH_{CH_4}} =\frac{-146.3x10^5kJ}{-890kJ/molCH_4} *\frac{16gCH_4}{1molCH_4} \\\\m_{CH_4}=2630112.36g=2630kg$

b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:

$n_{CH_4}=\frac{PV}{RT}=\frac{1atm*1000L}{0.082\frac{atm*L}{mol*K}*273K} =44.67mol$

Con ello, los kilogramos de metano que cuestan 0,45 €:

$44.67molCH_4*\frac{16gCH_4}{1molCH_4}*\frac{1kg}{1000g} =0.715kgCH_4$

Luego, aplicamos la regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

3 0

3 years ago

Which is the correct orbital diagram for carbon?

Brrunno [24]

Answer:

its 2p

Explanation:

In a neutral carbon atom, the 1s sublevel has one orbital with two electrons with opposite spins, represented by the arrows pointing in opposite directions. The 2s sublevel also has one orbital with two electrons, also with opposite spins. The 2p sublevel has three orbitals.

(i don"t understand this i just looked it up ._.

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3 years ago