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Elan Coil [88]
3 years ago
11

Which one has the greatest mass?

Chemistry
2 answers:
Shtirlitz [24]3 years ago
8 0
To determine the one with the greatest mass, we convert all options into the same units of mass as follows:

<span>1. 3.55 mol O atoms ( 16 g / mol ) = 56.8 g O
2. 4.52 g O atoms 
3. 0.0032 kg O2 molec ( 1000 g / 1kg ) ( 1 mol / 32 g ) ( 2 mol / 1 mol ) ( 16 g / mol) = 3.2 g O
4. 7.39 × 10^23 O2 molec ( 1 mol / 6.022x10^23 molecules) (2 mol / 1 mol)(16 g/mol) = 39.27 g O</span>
dexar [7]3 years ago
7 0

<u>Answer:</u> The correct answer is Option 1.

<u>Explanation:</u>

For the given options:

  • <u>Option 1:</u>  3.55 mole of O atoms

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Oxygen = 3.55 mol

Molar mass of Oxygen = 16 g/mol

Putting values in above equation, we get:

3.55=\frac{\text{Mass of oxygen}}{16g/mol}\\\\\text{Mass of oxygen}=56.8g

Mass of oxygen atoms = 56.8 g

  • <u>Option 2:</u> 4.52 g of O atoms

Mass of oxygen atoms = 4.52 g

  • <u>Option 3:</u> 0.0032 kg of O_2 molecule

Converting this into grams, we use the conversion factor:

1 kg = 1000 g

So, 0.0032 kg = 3.2 g

Mass of O_2 molecule = 3.2 g

  • <u>Option 4:</u> 7.39\times 10^{23} of O_2 molecule

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of atoms.

If, 6.022\times 10^{23} number of atoms occupies 32 grams of oxygen molecule.

So, 7.39\times 10^{23} number of atoms will occupy = \frac{32g}{6.022\times 10^{23}}\times 7.39\times 10^{23}=39.2g

Mass of O_2 molecule = 39.2 g

Hence, the greatest mass is coming out from option 1.

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Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
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  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

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3 years ago
How many moles of oxygen must be placed
umka21 [38]

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:  

PV = nRT  

where:  

P - pressure (in atm)  

V - volume (in L)  

n - amount of gas (in moles)  

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}  

T - temperature (in K)  

In the problem, we are given the values:  

P = 2.00 atm (3 significant figures)

V = 3.00 L  (3 significant figures)

n = ?

T = 25.0 degrees Celsius (3 significant figures)  

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:  

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15  

Therefore, for this problem,  

Temperature\ in \ K = 25.0 +273.15\\Temperature\ in \ K = 298.15  

Solving for n using the Ideal Gas Equation:  

n \ = \frac{PV}{RT}\\n \ = \frac{(2.00 \ atm) \ (3.00 \ L)}{(0.08206 \ \frac{L-atm}{mol-K})( 298.15 \ K)}  \\n \ = 0.245 \ mol

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures.

Learn More  

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697  

3. Learn more about Gay-Lussac's Law brainly.com/question/6534668

Keywords: Ideal Gas Law, Volume, Pressure

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1. Air shows the property of<br> a) N<br> b) 02<br> c) Both a) and b)<br> d) None of these
kupik [55]

Answer:

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Answer:

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Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR
ycow [4]

Answer:

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Explanation:

We know the volume of solution → 0.30 L

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Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L  = 1.32 M

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