Answer:
statement best describes the total number of carbon atoms during cellular
respiration in the fish is :
The total number of carbon atoms stays the same because the carbon from the carbon-containing food molecules is used to make molecules such as carbon dioxide
Explanation:
Respiration : It is a process in which energy from the "food" molecule is released in the form of ATP
ATP = Adenosine Triphosphate
There are two kind of respiration process:
1. In the presence of O2 = Aerobic Oxidation
2. In the absence of O2 = Anaerobic Oxidation
The breakdown of food into CO2 occur by three main process:
Glycolysis
Krebs cycle
Phosphorylation
The reaction for the Decomposition of the Glucose molecule is written as:

It is a oxidation - reduction reaction(Redox).
Here one substance is oxidised and other is reduced.
The number of Carbon atoms in reactant =6
It will produce = 6 CO2 in which the number of C=6
Hence ,
The total number of carbon atoms stays the same because the carbon from the carbon-containing food molecules is used to make molecules such as carbon dioxide
Answer: Electrons in bonding orbitals stabilize the molecule because they are between the nuclei. They also have lower energies because they are closer to the nuclei. Antibonding orbitals place less electron density between the nuclei. The nuclear repulsions are greater, so the energy of the molecule increases.
Explanation:
Fire is actually a chemical reaction. It's an oxidation reaction to be specific. When wood gets hot enough (the part of the wood that is burning) the large hydrocarbons break down to charred solids and a gas. The gas is what reacts with oxygen in the atmosphere to produced light, CO2 and H2O.
Answer:
b) pH = 9.25
Explanation:
- NH4+(aq) + H2O(l) ↔ NH3(aq) + H3O+(aq)
- NH3 + H2O ↔ NH4+ + OH-
- 2 H2O ↔ H3O+ + OH-
⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature
mass balance NH4+:
⇒ M NH4+ = [ NH4+ ] - [ OH- ]
∴ [ NH3 ] ≅ M NH4+ = 0.26 M
⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5
⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6
⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0
⇒ [ OH- ] = 1.859 E-5 M
⇒ pOH = - Log ( 1.859 E-5 )
⇒ pOH = 4.7305
⇒ pH = 14 - pOH = 9.269