If the given sequence is a geometric sequence, find the common ratio.

Mathematics

2 answers:

marusya05 [52]3 years ago

8 0

Answer:

d. 1/4

Step-by-step explanation:

The common ratio will be the ratio of any two adjacent terms:

(3/12)/(3/3) = (1/4)/1 = 1/4

Gala2k [10]3 years ago

5 0

Answer:

Step-by-step explanation:

If the sequence is geometric then a common ratio r will exist between consecutive terms.

$\frac{3}{12}$ ÷ 1 = $\frac{3}{12}$ = $\frac{1}{4}$

$\frac{3}{48}$ ÷ $\frac{3}{12}$ = $\frac{1}{4}$

$\frac{3}{192}$ ÷ $\frac{3}{48}$ = $\frac{1}{4}$

$\frac{3}{768}$ ÷ $\frac{3}{192}$ = $\frac{1}{4}$

A common ratio of r = $\frac{1}{4}$

Hence sequence is geometric

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3 years ago

Solve.

baherus [9]

The correct answer is: [C]: " 5 " .
__________________________________________________________
→ " a = 5 " .
__________________________________________________________
Explanation:
__________________________________________________________

Given: " a + 1 <span>− 2 = 4 " ; Solve for "a" ;

4 + 2 = 6 ;

6 </span>− 1 = 5 ; → a = 5 ;

To check our work:

5 + 1 − 2 = ? 4 ?? ;

5 + 1 = 6 ;

6 − 2 = 4. Yes!

So the answer is: [C]: " 5 ".
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→ " a = 5 " .
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