3 years ago

If the given sequence is a geometric sequence, find the common ratio.

Mathematics

2 answers:

marusya05 [52]3 years ago

8 0

Answer:

d. 1/4

Step-by-step explanation:

The common ratio will be the ratio of any two adjacent terms:

(3/12)/(3/3) = (1/4)/1 = 1/4

Gala2k [10]3 years ago

5 0

Answer:

Step-by-step explanation:

If the sequence is geometric then a common ratio r will exist between consecutive terms.

$\frac{3}{12}$ ÷ 1 = $\frac{3}{12}$ = $\frac{1}{4}$

$\frac{3}{48}$ ÷ $\frac{3}{12}$ = $\frac{1}{4}$

$\frac{3}{192}$ ÷ $\frac{3}{48}$ = $\frac{1}{4}$

$\frac{3}{768}$ ÷ $\frac{3}{192}$ = $\frac{1}{4}$

A common ratio of r = $\frac{1}{4}$

Hence sequence is geometric

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