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hodyreva [135]
2 years ago
13

If the given sequence is a geometric sequence, find the common ratio.

Mathematics
2 answers:
marusya05 [52]2 years ago
8 0

Answer:

  d.  1/4

Step-by-step explanation:

The common ratio will be the ratio of any two adjacent terms:

  (3/12)/(3/3) = (1/4)/1 = 1/4

Gala2k [10]2 years ago
5 0

Answer:

d

Step-by-step explanation:

If the sequence is geometric then a common ratio r will exist between consecutive terms.

\frac{3}{12} ÷ 1 = \frac{3}{12} = \frac{1}{4}

\frac{3}{48} ÷ \frac{3}{12} = \frac{1}{4}

\frac{3}{192}  ÷ \frac{3}{48} = \frac{1}{4}

\frac{3}{768} ÷ \frac{3}{192} = \frac{1}{4}

A common ratio of r = \frac{1}{4}

Hence sequence is geometric

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To find x-intercept/zero, substitute y=0

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3 years ago
What is the answer for k=6x+100
postnew [5]

Answer:

x = k/6 - 50/3

Step-by-step explanation:

K=6x+100

--> Swap sides so that all variable terms are on the left hand side.

6x+100=k

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--> Divide both sides by 6.

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x = k-100/6

--> Divide k−100 by 6.

Answer : x = k/6 - 50/3

Hope this helps you!

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