You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
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Answer:
56972.17K
Explanation:
P = 4.06kPa = 4.06×10³Pa
V = 14L
n = 0.12 moles
R = 8.314J/Mol.K
T = ?
We need ideal gas equation to solve this question
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume the gas occupies
n = number of moles
R = ideal gas constant
T = temperature of the gas
PV = nRT
T = PV / nR
T = (4.06×10³ × 14) / (0.12 × 8.314)
T = 56840 / 0.99768
T = 56972.17K
Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa
Answer:
12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.
Explanation:
initially
3.0 atm 0 0
At equilibrium
(3.0-2p) p 3p
Equilibrium partial pressure of nitrogen gas = p = 0.90 atm
The expression of a pressure equilibrium constant will be given by :
12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.
Answer: Ok so the MOLE (mol) is a unit of measurement representing the amount of a substance that contains the same number of atoms as there are molecules in exactly 12 grams of carbon-12 (i.e., 6022X1023).
Explanation: And that's how it goes, I hope you understood it well!
Best regards (Pr. El Haji)
The answer is -60.57 = -60.6 KJ.
CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) +C2H2(g) H= -127.2 KJ
Hf C2H2 = 226.77
Hf Ca(OH)2 = -986.2
<span>Hf H2O = -285.83
Now,
</span><span>add them up. 226.77 - 986.2 + (2*285.83) = -187.77
</span><span>Add back the total enthalpy that is given in the question
-187.77+127.2 = -60.57 </span>
