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Travka [436]
4 years ago
12

Which of the following solutions is a good buffer system? which of the following solutions is a good buffer system? a solution t

hat is 0.10 m hcn and 0.10 m nacl a solution that is 0.10 m hcn and 0.10 m licn a solution that is 0.10 m hno3 and 0.10 m kno3 a solution that is 0.10 m naoh and 0.10 m hno3 a solution that is 0.10 m nacl and 0.10 m hc?
Chemistry
2 answers:
Luba_88 [7]4 years ago
7 0

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

A buffer is defined as the mixture of a weak acid with its conjugate base or vice versa. Thus:

A solution that is 0.10 M HCN and 0.10 M NaCl. <em>IS NOT A BUFFER. </em>The HCN is a weak acid but its conjugate base is CN⁻ that is not present in that solution.

* A solution that is 0.10 M HCN and 0.10 M LiCN. <em>IS A BUFFER. </em>The LiCN dissolves in water forming CN⁻, the conjugate base of HCN

A solution that is 0.10 M HNO₃ and 0.10 M KNO₃. <em>IS NOT A BUFFER. </em>HNO₃ is a strong acid, not a weak acid.

A solution that is 0.10 M NaOH and 0.10 M HNO₃. <em>IS NOT A BUFFER. </em>NaOH is a strong base and HNO₃ is a strong acid.

A solution that is 0.10 M NaCl and 0.10 M HCl. <em>IS NOT A BUFFER. </em>HCl is a strong acid.

I hope it helps!

Irina-Kira [14]4 years ago
4 0
Buffer is formed from weak acid and its salt with strong base (conjugate base) so the correct answer will be 0.1 M HCN and 0.1 M LiCN and all other choices are incorrect
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CH3 + HCl &lt;=&gt; CH3Cl + H2O
dmitriy555 [2]

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

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