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prohojiy [21]
3 years ago
11

Is muddy water a mixture or pure sub

Chemistry
2 answers:
xxMikexx [17]3 years ago
5 0
Muddy water is indeed a mixture
Alex787 [66]3 years ago
5 0
It is a mixture sub hope this helps!
You might be interested in
How many molecules are there in 560 grams of CoCl2?​
Marrrta [24]

Answer:

25.89  × 10²³ molecules

Explanation:

Given data:

Mass of CoCl₂ = 560 g

Number of molecules present = ?

Solution:

Number of moles of CoCl₂:

Number of moles = mass/molar mass

Number of moles = 560 g/ 129.84 g/mol

Number of moles = 4.3 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

4.3 mol ×  6.022 × 10²³ molecules /1 mol

25.89  × 10²³ molecules

5 0
3 years ago
1. inspiration meaning​
Furkat [3]

Answer:

inspiration means

the process of being mentally stimulated to do or feel something, especially to do something creative.

6 0
3 years ago
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How many electrons can the n = 4 shell hold?
uysha [10]

Answer: I think its 32 I'm not sure

Explanation:

6 0
3 years ago
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The kw for water at 0 °c is 0.12× 10–14 m2. Calculate the ph of a neutral aqueous solution at 0 °c.
jekas [21]

Answer:

pH = 7.46.

Explanation:

  • The ionization of water is given by the equation :

<em>H₂O(l) ⇄ H⁺(aq) + OH⁻(aq),</em>

<em></em>

  • The equilibrium constant (Kw) expression is:

<em>Kw = [H⁺][OH⁻] = 0.12 x 10⁻¹⁴.  </em>

<em></em>

in pure water and neutral aqueous solution, [H⁺] = [OH⁻]  

So, Kw = [H⁺]²

∴ 0.12 x 10⁻¹⁴ = [H⁺]²

∴ [H⁺] = 3.4 x 10⁻⁸ M.

∵ pH = - log [H⁺]  

pH = - log (3.4 x 10⁻⁸) = 7.46.

8 0
3 years ago
The formation of tert-butanol is described by the following chemical equation:
fomenos

Answer:

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

Explanation:

This reaction involves;

First the ionization of the tertiary halide to firm a carbocation

Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol

First step;

(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

This second step completes the reaction mechanism.

3 0
3 years ago
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