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ladessa [460]
3 years ago
13

Compared to a sodium atom in the ground state a sodium atom in the excited state must have ?

Chemistry
1 answer:
kipiarov [429]3 years ago
6 0
An electron with greater energy.

I hope this helps :)
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If 135.7 J of heat are added to 54.0 g of water initially at 25.0 °C . What is the final temperature of the water?
german

Answer:

The final temperature of the water is 25.6 °C.

Explanation:

We have,

Heat added to water is 135.7 J

Mass, m = 54 g

Initial temperature was 25 °C

It is required to find the final temperature of the water. The heat added when temperature is increased is given in terms of specific heat capacity as :

Q=mc(T_f-T_i)

T_f is final temperature

c is specific heat capacity, for water, c=4.184\ J/g^{\circ} C

So,

T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{135.7}{54\times 4.184}+25\\\\T_f=25.6^{\circ} C

So, the final temperature of the water is 25.6 °C.

3 0
4 years ago
The troposphere is the layer of the atmosphere where (4 points)
irakobra [83]
The troposphere is the lowest level of earths atmosphere. Cloud formations and weather conditions Are most commonly seen in this later. So the correct answer is B.
6 0
4 years ago
Consider this reaction:
madreJ [45]
11.2L / 22.4L/mol = . 5 mol H2 40g / 160g/mol = . 25 mol Br2.
5 0
3 years ago
How many electrons belong to a neutral atom with an atomic mass of 36 amu?
siniylev [52]
The answer is cannot determine
4 0
3 years ago
For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
IRISSAK [1]

Answer:

m_{Zn(OH)_2}=38.4g

Explanation:

Hello!

In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

Best regards!

5 0
3 years ago
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