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bazaltina [42]
3 years ago
8

a wheelchair ramp has a rise from the ground of 1 foot. the ramp has a length of 14 feet. to the nearest degree, find the angle

the ramp makes with the sidewalk. (the figure is not drawn to scale.)
Mathematics
1 answer:
sergey [27]3 years ago
6 0
The mnemonic SOH CAH TOA helps you remember the relevant trig relationship is
   Sin(α) = Opposite/Hypotenuse
   sin(α) = (1 ft)/(14 ft)
   α = arcsin(1/14) ≈ 4°

The angle the ramp makes with the sidewalk is 4°.
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Given the information in the diagram below, find the measure of angle N. Use RACE and complete sentences to show how you found t
Sonja [21]

Answer:

m<N = 76°

Step-by-step explanation:

Given:

∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).

m<J = 64° (given)

Required:

m<N

SOLUTION:

m<K = m<J (base angles of an isosceles ∆ are equal)

m<K = 64° (Substitution)

m<K + m<J + m<JLK = 180° (sum of ∆)

64° + 64° + m<JLK = 180° (substitution)

128° + m<JLK = 180°

subtract 128 from each side

m<JLK = 180° - 128°

m<JLK = 52°

In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.

Thus:

m<MLN = m<JKL (vertical angles are congruent)

m<MLN = 52°

m<M = m<MLN (base angles of isosceles ∆MNL)

m<M = 52° (substitution)

m<N + m<M° + m<MLN = 180° (Sum of ∆)

m<N + 52° + 52° = 180° (Substitution)

m<N + 104° = 180°

subtract 104 from each side

m<N = 180° - 104°

m<N = 76°

4 0
3 years ago
Justin is marking a border for a garden. He walks 200 feet to the east, then turns and
ELEN [110]

Answer:

d = 233.23 feet

Step-by-step explanation:

Given that,

Justin walks 200 feet to the east, then turns and  walks 120 feet due south.

We need to find the total distance walked by Justin. Let the distance be d.

We can use the Pythagoras theorem to find it such that,

d=\sqrt{d_1^2+d_2^2} \\\\d=\sqrt{200^2+120^2} \\\\d=233.24\ feet

So, he walk 233.23 feet in all.

3 0
2 years ago
Can someone please answer. There is only one problem. There is a picture. Thank you!!!
Rainbow [258]
The number of permutations of the 25 letters taken 2 at a time (with repetitions) is:25^{2}
The number of permutations of the 9 digits taken 4 at a time (with repetitions) is:
9^{4}
Each permutation of letters can be taken with each permutation of digits, therefore the total number of possible passwords is:
25^{2}\times 9^{4}=4,100,625

6 0
3 years ago
Read 2 more answers
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
Pls help me! I will mark brainliest if you are correct
Aleksandr [31]

Answer:

I' would say A but C could be a possibility.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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