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Mila [183]
3 years ago
15

7. Do you have any reservations about taking this course? Explain. How can I help?

Chemistry
1 answer:
Pavel [41]3 years ago
3 0

Answer:

Reservations means to say, are there any thoughts you have about this course that are negative. And what can your teacher do to help you excel, or succeed in this course. Good luck to you, and remember to take deep breathes when you need a break.

Explanation:

You might be interested in
What is meant by atomic number?
SpyIntel [72]
C I hope I help good luck
8 0
2 years ago
write chemical equations of photosynthesis and cellular respiration and show if carbon is oxidized or reduced
irina [24]

Answer:

Explanation:

  • The chemical reaction for cellular respiration  is as follows -

C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂  ( Carbon dioxide ) +  6H₂O ( Water ) + 38 ATP molecules ( Energy ) .

This is an example of oxidation of carbon .

  • The chemical reaction for photosynthesis  is as follows -

6CO₂  ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂  ( Oxygen ).

This is an example of reduction of carbon .

6 0
2 years ago
How many molecules of N204 are in 85.0 g of N2O4?
alukav5142 [94]

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

4 0
3 years ago
59 Q.No. 28 b Hydrogen peroxide can act as oxidizing as well as reducing agent with example. ​
professor190 [17]

Answer:

Hydrogen peroxide can function as an oxidizing agent as well as reducing agent. 

H2O2 act as oxidizing agent in acidic medium.

Explanation:

Example : 2FeSO4 +H2SO4 +H2O2 —>

(ferrous sulphate)

Fe2(SO4)3 +2H2O

(ferric sulphate)

3 0
2 years ago
. Consider the following half-reactions:
Vedmedyk [2.9K]

d. Fe(s) and Al(s)

<h3>Further explanation</h3>

In the redox reaction, it is also known  

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

The electrodes which are easier to reduce than hydrogen (H), have E cells = +

The electrodes which are easier to oxidize than hydrogen have a sign E cell = -

So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)

The metal  : d. Fe(s) and Al(s)

7 0
3 years ago
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