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Jobisdone [24]
3 years ago
11

The molar mass of aluminum oxide (Al2O3) is 102.0 g/mol. What is the correct way to write the inverted molar mass of aluminum ox

ide as a conversion factor?
Chemistry
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

B on edge

Explanation:

ki77a [65]3 years ago
6 0
The molar mass of aluminum oxide is 102.0 g/mol =>

     1 mol Al2 O3 = 102.0 g

=> 1 = 1 mol Al2O3 / 102.0 g = 1 / 102.0 g/mol

So, the conversion factor, which you can use to convert mass in grams of aluminum oxide to number of moles is 1 / 102.0 g/mol.

Answer: 1 / 102.0 g/mol

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Read 2 more answers
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

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Cross multiply to express in linear form

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