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Jobisdone [24]
3 years ago
11

The molar mass of aluminum oxide (Al2O3) is 102.0 g/mol. What is the correct way to write the inverted molar mass of aluminum ox

ide as a conversion factor?
Chemistry
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

B on edge

Explanation:

ki77a [65]3 years ago
6 0
The molar mass of aluminum oxide is 102.0 g/mol =>

     1 mol Al2 O3 = 102.0 g

=> 1 = 1 mol Al2O3 / 102.0 g = 1 / 102.0 g/mol

So, the conversion factor, which you can use to convert mass in grams of aluminum oxide to number of moles is 1 / 102.0 g/mol.

Answer: 1 / 102.0 g/mol

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When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i
Ipatiy [6.2K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)

Hence, the net ionic equation is written above.

8 0
3 years ago
How will the following changes affect the mole fraction of chlorine gas, χcl2, in the equilibrium mixture.?
sammy [17]
If the reaction is represented by:
PCl₃ + Cl₂ <-> PCl₅ (exothermic)

the mole fraction of chlorine in the equilibrium mixture will change according to the following:
Decrease the volume: decrease
Increase the temperature: increase
Increase the volume: increase
Decrease the temperature: decrease
4 0
3 years ago
Two major discoveries of the gold foil experiment
tiny-mole [99]
Rutherford's gold foil experiment proved that there was a small, dense, positively charged nucleus at the center, which contained most of the mass of the atom. Which contained electrons orbiting the nucleus.
5 0
3 years ago
If 35.0 mL of water in a graduated cylinder is displaced by 8.00 mL
sdas [7]

Answer:

<h2>0.52 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question

volume = final volume of water - initial volume of water

volume = 35 - 8 = 27 mL

We have

density =  \frac{14}{27}  \\  = 0.518518...

We have the final answer as

<h3>0.52 g/mL</h3>

Hope this helps you

3 0
2 years ago
Compounds X and Y both have the formula C7H14. Both X and Y react with one molar equivalent of hydrogen in the presence of a pal
ArbitrLikvidat [17]

Answer:

See explanation and image attached

Explanation:

Alkenes undergo hydrogenation to give the corresponding alkanes. Where the structure of the original alkene is unknown, we can deduce the structure of the alkene from the structure of the products obtained when it undergoes various chemical reactions.

Now, the fact that we obtained 2-methylhexane upon hydrogenation and the two compounds had different heats of hydrogenation means that the two compounds were geometric isomers. The original compounds must have been cis-2-methyl-3-hexene and trans-2-methyl-3-hexene.

When reacted with HCl, the same compound C7H15Cl is formed because the stereo chemistry is removed.

However, we know that the trans isomer is more stable than the cis isomer hence the cis isomer always has a higher heat of hydrogenation than the trans isomer. Thus X is cis-2-methyl-3-hexene.

4 0
3 years ago
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