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Hitman42 [59]
3 years ago
15

A syringe containing 12.0 mL of dry air at 25 C is placed in a sterilizer and heated to 100.0 C. The syringe is sealed, but th

e plunger can move and the volume can change. What is the volume of the air in the syringe at 100.0 C, assuming no change in pressure?
Physics
1 answer:
monitta3 years ago
5 0

Answer:

15.01 Liters

Explanation:

T₁ = Initial temperature = 25°C = 298.15 K

T₂ = Final temperature = 100°C = 373.15 K

V₁ = Initial volume = 12 mL

Here, pressure is constant so we apply Charles Law

\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\Rightarrow {V_2}=\frac{V_1}{T_1}\times T_2\\\Rightarrow {V_2}=\frac{12}{298.15}\times 373.15\\\Rightarrow {V_2}=15.01 L

∴ Final volume at 100°C is 15.01 Liters.

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The density of water is 1000kg/m3 and the density of ice is 900kg/m3. When 0.050 m3 of water is frozen, what will be the new vol
Bingel [31]
Sorry if this answer is a bit late...

We know that the volume of the water is 0.5 cube meters.

The density of water is 1.000 g/m^3 (that's the real density of water... maybe typos?)

The density of ice is 0.900 g/m^3 (that's the approximate density of ice)

First, let's multiply the volume of water by the density of the water to get the mass, since we know that the mass does not change with the ice gets frozen.

0.5 * 1.000 = 0.500 g

Now, let's divide that by the density of ice to get the volume of the ice.

0.500 / 0.900 = 5/9 cube meters

≈ 0.556 cube meters.

The volume of the ice is 5/9 or 0.556 cube meters.

Have an awesome day! :)
4 0
3 years ago
What would the final volume of 40 L of gas at 80 pascals be if the pressure increases to 130 pascals?
melomori [17]

Answer:

Final volume, V2 = 24.62 L

Explanation:

Given the following data;

Initial volume = 40 L

Initial pressure = 80 Pa

Final pressure = 130 Pa

To find the final volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

80 * 40 = 130V_{2}

3200 = 130V_{2}

V_{2} = \frac {3200}{130}

V_{2} = 24.62

Final volume, V2 = 24.62 Liters

5 0
2 years ago
I need helpppppppppppppppppp!
allsm [11]

Answer:

i think its B

Explanation:

but check it before do it  

3 0
3 years ago
Read 2 more answers
Suppose you are measuring double‑slit interference patterns using an optics kit that contains the following options that you can
svetlana [45]

Answer:

3.6 m

Explanation:

\lambda_R = 650 \ nm\\\\\lambda_R = 650*10^{-9} m\\\\L \ should \ be \ minimum \\\\i.e \  0.25 \ mm\\\\= 0.25 *10^{-3} m

\lambda_R = 700 \ nm\\\\\lambda_R = 700*10^{-9} m\\\\

Also

\beta = 1 \ mm \ fringe \  width

D_{min} = \frac{\beta d}{\lambda}\\\\D_{min} = \frac{10^{-3}*0.25*10^{-3}}{700*10^{-9}}\\\\D_{min} = 3.57 \\D_{min} =  3.6 m

Therefore, the minimum distance L  you can place a screen from the double slit that will give you an interference pattern on the screen that you can accurately measure using an ordinary 30 cm (12 in) ruler. = 3.6 m

4 0
3 years ago
A truck of mass 200kg rests on an inclined plane hindered from rolling down the surface by a storing sprint whose force constant
mixas84 [53]

Answer:

1.92 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 200 Kg

Spring constant (K) = 10⁶ N/m

Workdone =?

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass (m) = 200 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = m × g

F = 200 × 9.8

F = 1960 N

Next we shall determine the extent to which the spring stretches. This can be obtained as follow:

Spring constant (K) = 10⁶ N/m

Force (F) = 1960 N

Extention (e) =?

F = Ke

1960 = 10⁶ × e

Divide both side by 10⁶

e = 1960 / 10⁶

e = 0.00196 m

Finally, we shall determine energy (Workdone) on the spring as follow:

Spring constant (K) = 10⁶ N/m

Extention (e) = 0.00196 m

Energy (E) =?

E = ½Ke²

E = ½ × 10⁶ × (0.00196)²

E = 1.92 J

Therefore, the Workdone on the spring is 1.92 J

3 0
2 years ago
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