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3 years ago

15

A syringe containing 12.0 mL of dry air at 25 C is placed in a sterilizer and heated to 100.0 C. The syringe is sealed, but th

e plunger can move and the volume can change. What is the volume of the air in the syringe at 100.0 C, assuming no change in pressure?

1 answer:

monitta3 years ago

5 0

Answer:

15.01 Liters

Explanation:

T₁ = Initial temperature = 25°C = 298.15 K

T₂ = Final temperature = 100°C = 373.15 K

V₁ = Initial volume = 12 mL

Here, pressure is constant so we apply Charles Law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\Rightarrow {V_2}=\frac{V_1}{T_1}\times T_2\\\Rightarrow {V_2}=\frac{12}{298.15}\times 373.15\\\Rightarrow {V_2}=15.01 L$

∴ Final volume at 100°C is 15.01 Liters.

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From the newton's equation

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If you insert a crimp pin incorrectly, the ratcheted crimp tool will not sufficiently crimp the tabs. As a result, the wire may not fully conduct with the pin and the pin will be damaged.

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3 years ago

In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The

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Answer:

0.615 m

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We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, <em>u</em> = 0.00 m/s

Distance, <em>s</em> = 4.19 m

Time, <em>t</em> = 0.601 s

We use the equation

$s = ut+\frac{1}{2}at^2$

With <em>u</em> = 0.00 m/s,

$s = \frac{1}{2}at^2$

$a = \dfrac{2s}{t^2}$

$a = \dfrac{2\times4.19\text{ m}}{(0.601\text{ s})^2} = 23.2\text{ m/s}^2$

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$F = (13.1\text{ kg})(23.2\text{ m/s}^2) = 303.92 \text{ N}$

From Hooke's law, the extension, <em>e</em>, of a string is given by

$e = \dfrac{F}{k}$

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3 years ago

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babymother [125]

Answer:

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Thus her angular speed (in rev/s) when her arms and one leg open outward is $1.56\frac{rev}{s}$

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