If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:

where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:

the magnitude of the force changes as follows:

so, the force increases by a factor 4.
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Answer:
Explanation:
The equation for Power is
P = Work/time to do work and the equation for work is
Work = FΔx
We first need to find the amount of work done, then we can find the power it took to do that work.
W = 2000(9.8)(28) so
W = 550,000 N*m
Now we fill that into the power equation:
gives us
P = 18000 Watts. But we need kW, so we divide by 1000 to get
P = 18 kW of power.
Answer:
The west component of the given vector is - 42.548 meters.
Explanation:
We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

Where:
- Horizontal component of vector distance, measured in meters.
- Vertical component of vector distance, measured in meters.
Let suppose that east and north have positive signs, then we get the following expression:
![(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-45%5Ccdot%20%5Ccos%2019%5E%7B%5Ccirc%7D%2C%20-45%5Ccdot%20%5Csin%2019%5E%7B%5Ccirc%7D%29%5C%2C%5Bm%5D)
![(x, y) = (-42.548,-14.651)\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-42.548%2C-14.651%29%5C%2C%5Bm%5D)
The west component corresponds to the first component of the ordered pair. That is to say:

The west component of the given vector is - 42.548 meters.
I honestly don't see anything above. But 'H' on a weather map usually shows the center of a high-pressure system.