3 years ago

A 70 kg person running at 4 m/s what is the kinetic energy

Physics

1 answer:

gladu [14]3 years ago

3 0

Let:

m = mass (kg)

v = velocity (m/s)

KE = 0.5m(v^2)

KE = 0.5(70)(4^2)

KE = 560 Joules.

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A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det

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Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

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$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

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3 years ago