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2 years ago

A gas has a volume of 5.00 L at 20 degrees Celsius. What is the volume of gas at 150 degrees Celsius.

Chemistry

1 answer:

WARRIOR [948]2 years ago

5 0

Answer:

7.22 L

Explanation:

From the question,

Applying Charles law,

V₁/T₁ = V₂/T₂...................... Equation 1

Where V₁ = Initial volume of gas, V₂ = Final volume of gas, T₁ = Initial Temperature of gas in Kelvin, T₂ = Final Temperature of gas in Kelvin

Make V₂ the subject of the equation

V₂ = (V₁×T₂)/T₁................. Equation 2

Given: V₁ = 5.00 L, T₁ = 20 °C = (20+273) K = 293 K, T₂ = 150 °C = (150+273) K = 423 K

Substitute these value into equation 2

V₂ = (5.00×423)/293

V₂ = 7.22 L

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ZanzabumX [31]

Answer:

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Explanation:

Using the derived expression from Arrhenius Equation

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Given that:

time $t_1$ = 8.3 days = (8.3 × 24 ) hours = 199.2 hours

time $t_2$ = 10.6 hours

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Temperature $T_2$ = 30° C = (30+ 273) = 303 K

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Since $(\frac{k_2}{k_1}=\frac{t_2}{t_1})$

Then we can rewrite the above expression as:

$In \ (\frac{t_2}{t_1}) = \frac{E_a}{R}(\frac{T_2-T_1}{T_2*T_1})$

$In \ (\frac{199.2}{10.6}) = \frac{E_a}{8.314}(\frac{303-273}{273*303})$

$2.934 = \frac{E_a}{8.314}(\frac{30}{82719})$

$2.934 = \frac{30E_a}{687725.766}$

$30E_a = 2.934 *687725.766$

$E_a = \frac{2.934 *687725.766}{30}$

$E_a =67255.58 \ J/mol$

$E_a =67.2 \ kJ/mol$

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3 years ago

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