Answer:
7.22 L
Explanation:
From the question,
Applying Charles law,
V₁/T₁ = V₂/T₂...................... Equation 1
Where V₁ = Initial volume of gas, V₂ = Final volume of gas, T₁ = Initial Temperature of gas in Kelvin, T₂ = Final Temperature of gas in Kelvin
Make V₂ the subject of the equation
V₂ = (V₁×T₂)/T₁................. Equation 2
Given: V₁ = 5.00 L, T₁ = 20 °C = (20+273) K = 293 K, T₂ = 150 °C = (150+273) K = 423 K
Substitute these value into equation 2
V₂ = (5.00×423)/293
V₂ = 7.22 L
