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3 years ago

Electromagnetic waves differ from each other in

Chemistry

2 answers:

Viefleur [7K]3 years ago

7 0

The answer is b, wavelength only.

Leokris [45]3 years ago

4 0

The answer is b. wavelength only

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All of the following are part of the electromagnetic spectrum but

Lelechka [254]

Your answer is radio waves

6 0

3 years ago

Please help me on this I’ll give 30 points

Rufina [12.5K]

Answer:

1. 10.66 moles of Al

2. 2.5 moles of Al₂O₃

3. 143.87 g of SO₂

Explanation:

The balance chemical equation is as follow,

4 Al + 3 O₂ → 2 Al₂O₃

According to balance chemical equation,

3 moles of O₂ required = 4 moles of Al

So,

8 moles of O₂ will require = X moles of Al

Solving for X,

X = 8 mol × 4 mol / 3 mol

X = 10.66 moles of Al

According to balance chemical equation,

4 moles of Al produced = 2 moles of Al₂O₃

So,

5 moles of Al will produce = X moles of Al₂O₃

Solving for X,

X = 5 mol × 2 mol / 4 mol

X = 2.5 moles of Al₂O₃

The balance chemical equation for the oxidation of carbon disulfide is as follow;

CS₂ + 3 O₂ → CO₂ + 2 SO₂

Step 1: <u>Calculate Moles of CS₂ as;</u>

Moles = Mass / M.Mass

Moles = 85.5 g / 76.14 g/mol

Moles = 1.12 moles of CS₂

Step 2: <u>Find out moles of SO₂ as;</u>

According to balance chemical equation,

1 mole of CS₂ produced = 2 moles of SO₂

So,

1.12 moles of CS₂ will produce = X moles of SO₂

Solving for X,

X = 1.12 mol × 2 mol / 1 mol

X = 2.24 moles of SO₂

Step 3: <u>Calculate Mass of SO₂ as;</u>

Mass = Moles × M.Mass

Mass = 2.24 mol × 64.06 g/mol

Mass = 143.87 g of SO₂

4 0

3 years ago

What is the lewis dot structure of NaBr

Anon25 [30]

<span><span>LiF, LiCl, LiBr, LiI, LiAtNaF, NaCl, NaBr, NaI, NaAtKF, KCl, KBr, KI, KAt</span><span>RbF, RbCl, RbBr, RbI, RbAt CsF, CsCl, CsBr, CsI, CsAt FrF, FrCl, FrBr, FrI, FrAt<span>
</span></span></span>

3 0

3 years ago

A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L

NeTakaya

Answer:

$\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}$

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

$P_1V_1=P_2V_2$

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

$25.0 \ L * 2.05 \ atm = P_2V_2$

The volume is decreased to 14.5 liters, but the pressure is unknown.

$25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L$

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

$\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}$

$\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2$

The units of liters cancel.

$\frac {25.0 * 2.05 \ atm }{14.5 }=P_2$

$\frac {50.25\ atm }{14.5 }=P_2$

$3.53448276 \ atm = P_2$

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

$3.53 \ atm \approx P_2$

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0

2 years ago

If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--> 2NH3

djverab [1.8K]

1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3

the answer thus would be 68 grams of NH3

5 0

3 years ago