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Tems11 [23]
3 years ago
14

A flask contains an equal mixture of oxygen and argon. Which of the following statements is true about the effusion of the gases

?
Argon will effuse 1.07 times faster than oxygen.

Oxygen will effuse 1.19 times faster than argon.

Oxygen will effuse 5.29 times slower than argon.

Argon will effuse 1.48 times slower than oxygen.
Chemistry
1 answer:
frozen [14]3 years ago
8 0
Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
Mr Argon = 40
Effusion Oxygen = 1/√32
Effusion Argon = 1/√40
Effusion Oxygen / Effusion Argon = √(40) / √(32)
=√(40/32) = √(5/4) = 1.19
Thus, Oxygen will effuse 1.19 times faster than Argon. The second option is correct.
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Which element has two valence electrons?
Colt1911 [192]

Answer:

It is A) Calcium

Explanation:

Calcium has an electronic configuration of 2,8,8,2

6 0
2 years ago
Read 2 more answers
Why is the composition of the vapor different from the composition of the solution?
BaLLatris [955]
If there is solution with nonvolatile solute (<span>substance that does not readily </span>evaporate<span> into a </span>gas) <span>only the pure vapor of the solvent is present above the solution and solute stays in solution and do not enters vapor above solution. This is because nonvolatile solute has slow rate of evaporation and low vapore pressure.
If solution has two volatile components, composition of the vapor depends on vapor pressures of the components according </span><span>Raoult's Law.</span>
8 0
3 years ago
Express the following in liters at STP:<br><br><br><br> 6.62 x 10-3 moles HF
serious [3.7K]

Answer:

The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L

Explanation:

Given data:

Number of moles of HF =  6.62×10⁻³ mol

Volume of HF in litter at STP = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Standard temperature = 273 K

Standard pressure = 1 atm

Now we will put the values in formula.

1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K

V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K  / 1 atm

V = 148.38×10⁻³ L

Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.

8 0
3 years ago
PLEASE HELP ASAP!!!!
Vsevolod [243]

Answer:

The answer to your question is  C = 0.037 cal/g°C

Explanation:

Data

mass of the wire = m = 237 g

temperature 1 = T1 = 25°C

temperature 2 = T2 = 107°C

Heat = Q = 722 cal

Specific heat = C

Process

1.- Write the formula to find the specific heat

            Q = mC(T2 - T1)

-Solve for C

            C = Q / m(T2 - T1)

2.- Substitution

             C = 722 / 237(107 - 25)

3.- Simplification

              C = 722 / 237(82)

              C = 722 / 19434

4.- Result

               C = 0.037 cal/g°C

4 0
3 years ago
Gas Law
Ratling [72]

69 mmHg pressure is exerted by oxygen if 40% of the gas pressure is exerted by the oxygen gas.

<h3>What is pressure?</h3>

Pressure is defined to be the amount of force exerted per area

40% of pressure is exerted by oxygen gas.

So, 60% of pressure will be exerted by carbon dioxide gas.

60% of 115 mmHg = 69 mmHg

Hence, 69 mmHg pressure is exerted by oxygen if 40% of the gas pressure is exerted by the oxygen gas.

Learn more about pressure here:

brainly.com/question/15175692

#SPJ1

3 0
2 years ago
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