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pH of solution = 13.033
<h3>Further explanation</h3>Given
2.31 g Ba(OH)₂
250 ml water
Required
pH of solution
Solution
Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base
So we use a strong base formula to find the pH
[OH ⁻] = b. Mb where
b = number of OH⁻ /base valence
Mb = strong base concentration
Molarity of Ba(OH)₂(MW=171.34 g/mol) :
Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)
[OH⁻]= 2 . 0.054
[OH⁻] = 0.108
pOH= - log 0.108
pOH=0.967
pOH+pH=14
pH=14-0.967
pH=13.033
Answer:
The pH of the HCl solution is 3.9
Explanation:
Knowing the molar mass of HCl (36.5g/mol) it is possible to calculate the number of moles of HCl in the solution,
of HCl
HCl is a strong acid and when added to water will form H+ and Cl-, thus the moles of HCl are equal to moles of H+ in 354 mL of water
The concentration of protons in the solutions is .
The expression used to calculate the pH is
Hence, the pH of the HCl solution is 3.9 and Pepsi has a pH of 3.4 approximately, so they have almost the same pH.
Answer:
i)
ii)
ii)
Explanation:
As the initial and final states of the sample are the same, the ΔU of the sample is, for the three cases
since
i)Reversibly so
can be calculated by
and because of the first law of thermodynamics
ii)Irreversibly with
we can calculate by the law of ideal gases
then w can be calculated by
and
iii)a free expansion so
(there's no work at vaccum) and