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Vesnalui [34]
3 years ago
6

What contribution did these scientists make to atomic models of the atom?

Chemistry
1 answer:
SashulF [63]3 years ago
7 0

Answer:

Explanation:

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

In 1897, J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

The Bohr model shows the atom as a small, positively charged nucleus surrounded by orbiting electrons. Bohr was the first to discover that electrons travel in separate orbits around the nucleus and that the number of electrons in the outer orbit determines the properties of an element.

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The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 7 g of this radioactive gas. (a) Find a func
Vlad1618 [11]

Answer:

misteri Cell ini quest ia half-life of beauty of misteri best, of Cell can't answer =

Explanation:

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5 0
3 years ago
If you have 150 grams of s8, how many moles of so2 can you make?
ruslelena [56]

Answer : You can make 4.68 moles of SO₂

Explanation:

Step 1 : Write balanced equation.

S₈ can combine with oxygen to form SO₂ gas. The balanced equation for this reaction is written below.

S_{8}  + 8 O_{2} \rightarrow 8 SO_{2}

Step 2 : Find moles of S₈

The formula to calculate mol is

mole = \frac{grams}{MolarMass}

Molar mass of S₈ is 256.5 g/mol

mole = \frac{150grams}{256.5 g/mol}

mole = 0.585 mol

we have 0.585 mol of S₈

Step 3: Use mole ratio to find moles of SO₂

The mole ratio of S₈ and SO₂ can be found using balanced equation which is 1:8

That means 1 mol of S₈ can form 8 moles of SO₂.

Let us use this as a conversion factor to find moles of SO₂

0.585 mol (S_{8}) \times \frac{8 mol (SO_{2})}{1 mol (S_{8})}  = 4.68 mol

Therefore we have 4.68 moles of SO₂

4 0
3 years ago
Read 2 more answers
When a sample of a gas is heated in a sealed, rigid container from 200. K to 400. K, the pressure exerted by the gas is:
gavmur [86]
When a sample of a gas is heated in a sealed, rigid container from 200 degree Kelvin to 400 degree Kelvin, the pressure exerted by the gas is increased by a factor 2. Heating any gas actually increases the volume of the gas within a container. As the temperature of the gas rises, the molecules of the gas start moving faster and start striking the walls of the container in which it is kept with more force. The volume of the container tries to expand to accommodate the fast colliding molecules of the gas.


5 0
3 years ago
I will mark brainlist please help
Lostsunrise [7]

Answer: 20) 2365 g

21) 22.39 grams.

22) 29.99 g

Explanation: 20) molarity is the no of moles of solute per unit volume.

We can calculate amount of CaCl2 required to prepare 0.1 M CaCl2 1000 ml solution.

we know that to prepare one ltr of 1 M solution of CaCl2 111 g required

Now consider x gram will require to prepare to

so that comparing above both condition

1000ml ×1M×X g=1000ml×0.1M×111g

X= 11.1 gram

X= 11.1 g of CaCl2

Hence 11.1 g of CaCl2 would be dissolved in 1.0L of a 0.100 M solution of CaCl2

21) How many moles of CaCl₂ in that solution?

;

;

.

What's the mass of that 0.20172 moles of CaCl₂?

Molar mass from a modern periodic table:

Ca- 40.078;

Cl- 35.45.

Molar mass of CaCl₂:

.

Mass of that 0.20172 moles of CaCl₂:

22) its a 3.0m solution so 1 litre of solution contains 3 moles of NaOH, 250ml of solution contains 0.25x39.9971 g/mol, so 250ml of this solution contains 0.75x39.9971=29.99g, or if you round it up 30.0g

7 0
3 years ago
PLEASE HELP!
Basile [38]

Answer:

<u>49.54 g</u>

Explanation:

Let's take the masses of both calcium sulfate and sulfur dioxide formed.

Sulfur dioxide = 32 + 2(16) = <u>64 g</u>

Calcium sulfate = 40 + 32 + 4(16) = <u>136 g</u>

So, under ideal conditions, to produce 136 g of Calcium sulfate, we require 64 g of Sulfur dioxide.

But, it mentions the process is only 95% efficient.

Hence, taking the ratio :

\frac{64}{136} = \frac{0.95x}{100}

0.95x = \frac{64 \times 100}{136}

0.95x = \frac{6400}{136}

x = \frac{800}{17} \times \frac{20}{19}

x = \frac{16000}{323}

x = <u>49.54 g</u> (approximately)

6 0
2 years ago
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