0.753 is the answer for this question
10^(-0.123)=0.753
Lewis Structure of
Oxygen Difluoride is sketched as....
Step 1: Calculate the
total number of valence electrons present in OF₂. This is done by adding all valence electrons of each element. i.e...
Valence e⁻s of Oxygen = 6
Valence e⁻s of Fluorine-1 = 7
Valence e⁻s of Fluorine-2 = 7
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Total Valence e⁻s
20Step 2: Draw central element (O) in center surrounded by fluorine atoms. Now, sketch a single bonds between O and both F atoms. Now, subtract 2 electrons per single bond from total valence electrons.. i.e..
Total Valence e⁻s = 20
2 single bonds (2 × 2) = 4
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16Now, distribute remaining 16 electrons on each element to complete its
octet starting from most electronegative element.
Lewis structure of OF₂ is as follow,
Answer:
Sodium bicarbonate
Explanation:
Sodium bicarbonate ( NaHCO₃ ) -
Sodium bicarbonate , according to the IUPAC nomenclature , its name is sodium hydrogen carbonate ,and in common terms also refereed to as baking soda .
It is a white crystalline solid , it is basic in nature .
<u>The cation and anion of this salt are the sodium ion ( Na⁺) and the anion bicarbonate anion (HCO³⁻) .</u>
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