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Kruka [31]
3 years ago
6

CH3CN major species present when dissolved in water

Chemistry
2 answers:
mario62 [17]3 years ago
5 0
The major species present when CH3CN is dissolved in water are CH3+ and CN-. It doesn't completely dissociate in water since it is not a strong acid or strong base. Only a strong acid or base will dissociate completely in water. For example HCl dissociates into H+ and Cl-, and NaOH dissociates into Na+ and OH-.
Margaret [11]3 years ago
3 0

Answer: CH₃CN and H₂O.

Explanation:

1) The spieces present in a solution may be either the molecules, in case of covalent compounds, or ions, in case of ionic compounds that dissociate (ionize).

2) Both, CH₃CN and H₂O are covalent (polar covalent) substances, so they do not ionize and the spieces in the solution are the molecules per se.

3) In solution, the molecules of H₂O will solvate the molecules of CH₃CN, meaning that H₂O molecules are able to separate the molecules of CH₃N from each other, and so every molecule of CH₃CN will end surrounded by many molecules of H₂O.

This happens because the interaction between the polar molecules of the two different compounds is strong enough to overcome the intermolecular forces between the molecules of the same compound.

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Allene (1,2-propadiene) has point group D2d, itself is achiral because it has two planes of symmetry. ... An allene with substituents on one terminal carbon atom are unlike and substituent on other terminal carbon atoms are same, allene will be achiral. It will have one symmetry plane.

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4 0
4 years ago
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Calculate the second volumes. <br> 7.03 Liters at 31 C and 111 Torr to STP
DIA [1.3K]

The second volume :    V₂= 0.922 L

<h3> Further explanation </h3><h3>Given </h3>

7.03 Liters at 31 C and 111 Torr

Required

The second volume

Solution

T₁ = 31 + 273 = 304 K

P₁ = 111 torr = 0,146 atm

V₁ = 7.03 L

At STP :  

P₂ = 1 atm

T₂ = 273 K

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

0.146 x 7.03 / 304 = 1 x V₂/273

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4 0
3 years ago
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Alex17521 [72]
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List the following bond types in order of increasing strength: non-polar covalent bonds, ionic bonds, hydrogen bonds, polar cova
ss7ja [257]

Answer: Option (B) is the correct answer.

Explanation:

  • An ionic bond is formed by the sharing of electrons between two chemically combining atoms.

In an ionic bond, there occurs attraction between oppositely charged ions due to which there occurs strong forces of attraction between them. Therefore, ionic bonds are the strongest bonds.

  • A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, H_{2}O is a polar covalent compound. Partial opposite charges tend to develop on the atoms of a polar covalent compound.

  • A non-polar covalent bond is formed due to equal sharing of electrons between the combining atoms.

For example, Cl_{2} is a non-polar covalent molecule. No partial charges will be there on the atoms of a non-polar covalent molecule.

  • A hydrogen bond is defined as the bond formed between a hydrogen atom and an electronegative atom.

For example, in HCl compound there occurs hydrogen bonding.

In this type of bond, dipole-dipole attractive interactions tend to take place. And, strength of hydrogen bonds is very weak.

Thus, we can conclude that given bond types are arranged in order of increasing strength as follows.

      Hydrogen bonds < non-polar covalent bonds < polar covalent bonds < ionic bonds

8 0
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