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Kruka [31]
3 years ago
6

CH3CN major species present when dissolved in water

Chemistry
2 answers:
mario62 [17]3 years ago
5 0
The major species present when CH3CN is dissolved in water are CH3+ and CN-. It doesn't completely dissociate in water since it is not a strong acid or strong base. Only a strong acid or base will dissociate completely in water. For example HCl dissociates into H+ and Cl-, and NaOH dissociates into Na+ and OH-.
Margaret [11]3 years ago
3 0

Answer: CH₃CN and H₂O.

Explanation:

1) The spieces present in a solution may be either the molecules, in case of covalent compounds, or ions, in case of ionic compounds that dissociate (ionize).

2) Both, CH₃CN and H₂O are covalent (polar covalent) substances, so they do not ionize and the spieces in the solution are the molecules per se.

3) In solution, the molecules of H₂O will solvate the molecules of CH₃CN, meaning that H₂O molecules are able to separate the molecules of CH₃N from each other, and so every molecule of CH₃CN will end surrounded by many molecules of H₂O.

This happens because the interaction between the polar molecules of the two different compounds is strong enough to overcome the intermolecular forces between the molecules of the same compound.

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The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles

<h3>Balanced equation </h3>

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

<h3>How to determine the mole of oxygen needed </h3>

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

Therefore,

28 moles of water will be obtained from = 28 / 2 = 14 moles of oxygen

Thus, 14 moles of oxygen are needed for the reaction

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