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dexar [7]
3 years ago
12

If Jupiter were 10 times more massive, it would generate nuclear fusion in its core and be a star instead of a planet. If Jupite

r were 10 times more massive, it would generate nuclear fusion in its core and be a star instead of a planet.
A. True
B. False
Physics
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

See explanation

Explanation:

Jupiter’s diameter is in fact larger than that of the smallest star, at 140,000 kilometres against 121,000 km for the tiniest star.

However it is mass, not size, that counts. This determines the internal pressure that, if sufficiently high, can overcome the mutual repulsion of hydrogen nuclei and convert these to helium through nuclear fusion. This releases the huge amount of energy that makes stars shine.

If a large cloud of interstellar gas came Jupiter’s way, maybe the planet could gain enough extra mass to start fusion. Fusion would be short lived if it became a brown dwarf, an object midway between star and planet. If it accreted even more mass, just enough to become a true star, it would be a dim red dwarf. Its radiation would barely affect us and it wouldn’t look very different to now. A bigger worry would be Jupiter’s increased mass disrupting the solar system, not to mention the raised temperature of the sun, as a result of it capturing most of the gas cloud.

Exact figures are uncertain, but calculations suggest Jupiter would need to be 80 times as massive as it is to turn into a small red dwarf star. Another possibility, though, is a brown dwarf, which is a kind of half-star. This isn’t massive enough for ordinary hydrogen to fuse into helium as in most stars. Instead it uses the rarer hydrogen isotope deuterium.  It is estimated a brown dwarf needs to be about 13 times the mass of Jupiter.

OverLord2011 [107]3 years ago
5 0

Answer:

False

Explanation:

Let me put it in numbers. Jupiter has mass of 1.898x10^27Kg, make it 10 times as much and it becomes 1.898x10^28 Kg.

TRAPPIST-1, smallest star ever found has Mass of 1.77x10^29Kg, that is around 93 times larger than the mass of Jupiter.

Clearly 10 times as much is not enough to generate fusion reaction and become a star, in theory Jupiter must be at least 85 times larger than it's current mass to be able to generate fusion reaction and become a star.

So i think we can conclude that if Jupiter were to have 10 times of its own mass, it would not become a star, therefore the given statement is False.

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Identify where the solid would be found after distillation is complete.
dimaraw [331]

Bottom of the distillation flask

Explanation:

The solid in the mixture to be separate would be found at the bottom of the distillation flask.

Distillation is a separation technique for differentiating the components of mixtures based on the differences in their boiling points.

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  • The solutes are then left behind in the flask as the solvent boils out as vapor.
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8 0
3 years ago
A sphere of mass of 1.55 kg is accelerated upwards by a string to which the sphere is attached. Its speed increases from 2.81 m/
Mama L [17]

Answer:

The tension in the string is 16.24 N

Explanation:

Given;

mass of the sphere, m = 1.55 kg

initial velocity of the sphere, u = 2.81 m/s

final velocity of the sphere, v = 4.60 m/s

duration of change in the velocity, Δt = 2.64 s

The tension of the string is calculated as follows;

T =  ma  + mg\\\\T = m(a + g)\\\\where;\\\\a \ is \ upward \ acceleration \ of \ the \ sphere\\\\g \ is \ acceleration \ due \ to \ gravity =9.8 \ m/s^2\\\\a = \frac{\Delta V}{\Delta t} = \frac{v- u}{ t} = \frac{4.6 - 2.81 }{2.64} = 0.678 \ m/s^2

T = 1.55(0.678 + 9.8)

T = 1.55(10.478)

T = 16.24 N

Therefore, the tension in the string is 16.24 N

5 0
3 years ago
A 20 cm tall object is placed in front of a concave mirror with a radius of 31 cm. The distance of the object to the mirror is 9
Aloiza [94]

Answer:

The focal length of the concave mirror is -15.5 cm

Explanation:

Given that,

Height of the object, h = 20 cm

Radius of curvature of the mirror, R = -31 cm (direction is opposite)

Object distance, u = -94 cm

We need to find the focal length of the mirror. The relation between the focal length and the radius of curvature of the mirror is as follows :

R = 2f

f is the focal length

f=\dfrac{R}{2}

f=\dfrac{-31}{2}

f = -15.5 cm

So, the focal length of the concave mirror is -15.5 cm. Hence, this is the required solution.

4 0
3 years ago
if your mass is 72kg your textbooks in Madison has 3.7 kg and you and your textbook are separated by a distance of 0.33 M what i
S_A_V [24]

Answer:

1.63 X 10^-7N

Explanation:

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