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marin [14]
3 years ago
8

The de Broglie wave is produced only by sub atomic particle and photon. O True O False

Physics
1 answer:
Alina [70]3 years ago
8 0

Answer:

True

Explanation:

Matter can be in the form of a particle or a wave. This is known as the dual nature of matter. This concept was proposed by Louis de Broglie and was named after him. This phenomenon has been observed for all the elementary particles.

The de Broglie wavelength is given by

\lambda=\frac{h}{p}=\frac{h}{mv}

Where

h = Planck's constant

p = Particles momentum

m = Mass of particle

v = Velocity of particle

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C.an equal and opposite reaction
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A boy accidentally touch an electric cable and quickly withdrew his hand. Narrate the impulses involved in such action.
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Answer:

Quick action was in this as a thought of he knew he could die from this

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Zinc metal (Zn) and sulfur powder (s) undergo a chemical reaction to form zinc sulfide (ZnS) which equation represents this chem
dexar [7]

Zinc metal (Zn) reacts with sulfur (S) to create zinc sulfide (ZnS), and the chemical reaction is: Zn (s) + S (s) = ZnS (s).

Importance of Zinc (Zn) and sulfur (S):

  • Zinc(Zn) is a vital element that our systems need to absorb food and nutrients as well as create healthy skin and bones. Zinc(Zn) ions play a crucial role in a number of the body's enzymes.
  • Sulfur(S) is a pale yellow, tasteless, brittle solid that is also necessary for life. It is found in many proteins as well as the amino acids cysteine and methionine. It is a trace element found in bone minerals, bodily fluids, and lipids.

Chemical reaction -

In this experiment, heating a zinc(Zn) and sulfur(S) combination causes an interesting chemical reaction. A blinding flash of light, hot sparks, a hissing sound, and a cloud of white smoke in the shape of a mushroom are produced.

Therefore, the following chemical processes are taking place in the reaction: Zn (s) + S (s) = ZnS (s).

Learn more about Zinc(Zn) here:

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8 0
2 years ago
When light propagates from a material with a given index of refraction into a material with a smaller index of refraction, the s
Ket [755]
Hope this can help u
7 0
3 years ago
Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section
ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER  E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W /  ( E × π × P )     ...................1

put here all value

σ = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

1300 × 10^{-24} = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

solve it and we get W

W = 249.56 × 10^{-2}

so elastic partial width is 2.49 eV

8 0
3 years ago
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