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matrenka [14]
3 years ago
15

How long does it take a 100 kg rocket to increase speed from 10

Physics
1 answer:
oee [108]3 years ago
5 0

Answer:

76 seconds

Explanation:

Using the formula t=vf-vo/a, where t=time, vf= final velocity, v0= initial velocity, and a= acceleration, we can solve for your problem.

Plug in known variables...

t=200-10/a

we can solve for a by using the formula F=ma where f=force, m= mass, and a=acceleration and rearranging it to solve for a.

a=F/m

Plug in known variables...

a=250N/100kg

a=2.5m/s^2

Plug in our newly found acceleration of 2.5 m/s^2 into our first equation and solve....

t=190/2.5

t=76 seconds

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How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

5 0
2 years ago
You're driving down the highway late one night at 21 m/s when a deer steps onto the road 35 m in front of you. Your reaction tim
andreev551 [17]

Speed with which initially car is moving is 21 m/s

Reaction time = 0.50 s

distance traveled in the reaction time d = v t

d = 21 * 0.50 = 10.5 m

deceleration after this time = -10 m/s^2

now the distance traveled by the car after applying bakes

v_f^2 - v_i^2 = 2a d

0 - 21^2 = 2(-10)d

d = 22.05 m

so total distance moved before it stop

d = 22.05 + 10.5 = 32.55 m

so the distance from deer is 35 - 32.55 = 2.45 m

now to find the maximum speed with we can move we will assume that we will just touch the deer when we stop

so our distance after brakes are applied is d = 35 - 10.5 = 24.5 m

again by kinematics

v_f^2 - v_i^2 = 2 ad

0 - v^2 = 2(-10)(24.5)

v = 22.1 m/s

so maximum speed would be 22.1 m/s

5 0
3 years ago
Automobiles must be able to sustain a frontal impacl The automobile design must allow low speed impacts with little sustained da
valentinak56 [21]

Answer: the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Given that;

mass of vehicle m = 1000 kg

for a low speed test; V = 2.5 m/s

bumper maximum deflection = 4 cm = 0.04 m

First we determine the energy of the vehicle just prior to impact;

W_v = 1/2mv²

we substitute

W_v = 1/2 × 1000 × (2.5)²

W_v = 3125 J

now, the the effective design stiffness k will be:

at the impact point, energy of the vehicle converts to elastic potential energy of the bumper;

hence;

W_v = 1/2kx²

we substitute

3125 = 1/2 × k (0.04)²

3125 = 0.0008k

k = 3125 / 0.0008

k = 3906250 N/m

Therefore, the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

3 0
3 years ago
A ball with an initial velocity of 12 m/s is rolling up a hill. The ball accelerates at a rate of -2.6 m/s/s.
Anon25 [30]

Answer:

4.61 seconds

Explanation:

Given data

Initial velocity= 12m/s

acceleration= -2.6m/s^2

From the given data

we can find the time t

we know that

Acceleration= velocity/time

time= velocity/acceleration

time= 12/2.6

time= 4.61 seconds

4 0
3 years ago
Do mirrors reflect light
777dan777 [17]

Answer:

Yes, Mirror are a surface that reflects light more perfectly than ordinary objects.

Explanation:

8 0
3 years ago
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