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2 years ago

How long does it take a 100 kg rocket to increase speed from 10

Physics

1 answer:

oee [108]2 years ago

5 0

Answer:

76 seconds

Explanation:

Using the formula t=vf-vo/a, where t=time, vf= final velocity, v0= initial velocity, and a= acceleration, we can solve for your problem.

Plug in known variables...

t=200-10/a

we can solve for a by using the formula F=ma where f=force, m= mass, and a=acceleration and rearranging it to solve for a.

a=F/m

Plug in known variables...

a=250N/100kg

a=2.5m/s^2

Plug in our newly found acceleration of 2.5 m/s^2 into our first equation and solve....

t=190/2.5

t=76 seconds

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Answer:

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2 years ago

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A torsional pendulum consists of a disk of mass 450 g and radius 3.5 cm, hanging from a wire. If the disk is given an initial an

Montano1993 [528]

To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:

$\omega = 2\pi f$

$\omega = 2\pi (2.5)$

$\omega = 5\pi rad/s$

The angular displacement is given as the form:

$\theta (t) = \theta_0 cos(\omega t)$

In the equlibrium we have to $t=0, \theta(t) = \theta_0$ and in the given position we have to

$\theta(t) = \theta_0 cos(5\pi t)$

Derived the expression we will have the equivalent to angular velocity

$\frac{d\theta}{dt} = 2.7rad/s$

Replacing,

$\theta_0(sin(5\pi t))5\pi = 2.7$

Finally

$\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°$

Therefore the maximum angular displacement is 9.848°

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3 years ago

If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?

vladimir1956 [14]

Answer:

1.33

Explanation:

speed of light in vacuum, c = 3 x 10^8 m/s

speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

μ = (3 x 10^8) / (2.26 x 10^8)

μ = 1.33

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2 years ago

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