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3 years ago

How long does it take a 100 kg rocket to increase speed from 10

Physics

1 answer:

oee [108]3 years ago

5 0

Answer:

76 seconds

Explanation:

Using the formula t=vf-vo/a, where t=time, vf= final velocity, v0= initial velocity, and a= acceleration, we can solve for your problem.

Plug in known variables...

t=200-10/a

we can solve for a by using the formula F=ma where f=force, m= mass, and a=acceleration and rearranging it to solve for a.

a=F/m

Plug in known variables...

a=250N/100kg

a=2.5m/s^2

Plug in our newly found acceleration of 2.5 m/s^2 into our first equation and solve....

t=190/2.5

t=76 seconds

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Rick shoots a basketball at an angle of 35' from the horizontal. It leaves his hands 7 feet from the ground with a velocity of 2

Korvikt [17]

Given:

The angle of projection of the basketball, θ=35°

The height at which the ball leaves the hand, h=7 ft

The initial velocity of the basketball, v=20 ft/s

To find:

The parametric equations describing the shot.

Explanation:

The range, x of the basketball is given by,

$x=v\cos\theta t$

On substituting the known values,

$\begin{gathered} x=20\times\cos35\degree\times t \\ \implies x=16.4t \end{gathered}$

The change in the height, y of the basketball is given by,

$y=-v\sin\theta t+\frac{1}{2}gt^2$

Where g is the acceleration due to gravity.

On substituting the known values,

$\begin{gathered} y=-20\times\sin35\degree\times t+\frac{1}{2}\times32\times t^2 \\ \implies y=-11.5t+16t^2 \end{gathered}$

Final answer:

The parametric equations describing the shot are

$\begin{gathered} \begin{equation*} x=16.4t \end{equation*} \\ \begin{equation*} y=-11.5t+16t^2 \end{equation*} \end{gathered}$

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Kipish [7]

Answer:

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Explanation:

A protective apron or lab coat is important when working with acids because acids break down fabrics and can cause burns if the acids are strong.

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A strong acid ionizes completely in solution.
When they come in contact with a fabric, they break them down violently.
So, if they come in contact with the skin, it causes a violent break down of body tissues.
The apron acts a protective layer.

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