Open circuit ......fiend do
Given :
The mass of the balloon was 1890 kg and had a volume of 11,430 m3 .
The balloon floats at a constant height of 6.25m above the ground.
To Find :
The density of the hot air in the balloon.
Solution :
We know,
Volume × ( Density of surrounding air - Density of hot air ) = mass
Putting given values in above equation, we get :

Therefore, the density of hot air in the balloon is 1.125 kg m³.
64. 16x16 = 4 so 9x9 divided by 2 equals 7
Answer:
0.707m
Explanation:
from formula of range i.e R=Usin2Q/g
Since the plane is traveling at 100m/s horizontal to the surface of the earth, the crate will always have this horizontal velocity (neglecting air resistance) until it hits the ground. So the answer is 100m/s. Note the vertical speed continues to change as the crate accelerates downward toward earth (again neglecting air effects)