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3 years ago

HELP FOR BRAINLEST!!!!!!

Mathematics

2 answers:

joja [24]3 years ago

5 0

Answer:

its c.

Step-by-step explanation:

because when you add opposites its always zero

hope this helps

Luda [366]3 years ago

3 0

Answer:

Step-by-step explanation:

when adding a negative and positive number with the same value you will get zero

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A car that is traveling from one city to another has a velocity that is increasing at a constant slope of 3. If the car started

Masteriza [31]

Answer:

c is the answer

Step-by-step explanation:

It is the only graph that starts at (1,0)

and if you look closely the slope is 3

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3 years ago

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A pote that is 3.5 m tall casts a shadow that is 1.08 m long same time, a nearby building casts a shadow that is 35.5 m long How

meriva

Answer:

I ain't never seen 2 pretty bestfriends

Step-by-step explanation:

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2 years ago

A man travels from town x to town y at an average rate of 60 mph and returns at an average rate of 50 mph. He takes a 1/2 hour l

Georgia [21]

D/60 + D/50 = 2D/55 - 1/2

find common denominator ( 3300)

3300/60 = 55

3300/50 = 66

3300/55=60

so then you get 55D +66D= 60(2D)-1650

121D=120D-1650

D=1650 miles

check

1650/60 =27.5, 1650/50 = 33, 27.5 + 33 = 60.5 hours total

1650/55 = 30, 30 x 2 = 60

60.5-60 = 0.5 longer

so distance = 1650 miles

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3 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

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3 years ago

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olga_2 [115]

I believe that’s false, because for every x there should only be one y, and x(5) has two y’s (1 and 3)

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2 years ago

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