Answer:
trigonal bipyramidal, T-shaped
Explanation:
The quantum numbers for the last valence electron in nickel are (3, 2, 0, -½).
The electron configuration of nickel is [Ar]4s²3d⁸
The last electron added is a 3d electron, so <em>n</em> = 3 and <em>l</em> = 2.
We construct a table of quantum numbers.
<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u> </u><em><u>m</u></em><u>ₗ mₛ </u>
Sc 3 2 2 +½
Ti 3 2 1 +½
V 3 2 0 +½
Cr 3 2 -1 +½
Mn 3 2 -2 +½
Fe 3 2 2 -½
Co 3 2 1 -½
Ni 3 2 0 -½
The quantum numbers for the last electron in nickel are (3, 2, 0, -½).
Answer: Multiple covalent bonds may occur in atoms that contain carbon,nitrogen, or <u><em>oxygen</em></u>.
Answer:
Given: 42 g of N2
Solve for O2 mass that contains the same number of molecules to 42 g of N2.
Solve for the number of moles in 42 g of N2
1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles
Solve for mass of 1 mole of oxygen
1 mole of O2 = 16 g * 2 = 32 g per mole
Solve for the mass of 1.5 moles of oxygen
mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles
mass of 1.5 moles of O2 = 48 g
So 48 g of O2 contains the same number of molecules as 42 g of N2