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Katarina [22]
3 years ago
12

C). How many mole of oxygen would be produced from reacting 7 mole of HgO (mercury (II) oxide)?

Chemistry
1 answer:
Leni [432]3 years ago
3 0

Answer:

There will be produced 3.5 moles of oxygen (O2)

Explanation:

Step 1: Data given

Number of moles Mercury (II) oxide (HgO) = 7 moles

Step 2: The balanced equation

2HgO → O2 + 2Hg

Step 3: Calculate number of moles of O2

For 2 moles of Mercury (II) oxide (HgO) we produce 1 mol of O2 and 2 moles of Hg

For 7 moles of Mercury (II) oxide (HgO) we'll have 7/2 = 3.5 moles of O2

There will be produced 3.5 moles of oxygen (O2)

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When 440.23 grams of iron(III) oxide are reacted with hydrogen gas, the amount of iron produced will be 307.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

Fe_2O_3 + 3H_2 --- > 2Fe + 3H_2O

The mole ratio of iron(III) oxide to produced iron is 1:2.

Mole of 440.23 iron(III) oxide = 440.23/159.69 = 2.76 moles

Equivalent mole of produced iron = 2.76 x 2 = 5.52 moles

Mass of 5.52 moles of iron = 5.52 x 55.8 = 307.66 grams

More on stoichiometric calculations can be found here; brainly.com/question/27287858

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