This means that the horizontal force is 750sin(25°). To be able to move the truck, force applied must be greater than static friction, which equals to its coefficient (0.77) x normal contact force (= weight)
Hence, 750sin(25°) = 0.77mg. m = 750sin(25°)/(0.77g)
What are the answer choices, if there are any?
<em>Answer</em><em>:</em><em> </em> The complementary relationship indicated by the Newton's second law...
For a given applied force the acceleration of the trolley is inversely proportional to it's mass.