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konstantin123 [22]
4 years ago
5

A drone drops a package on a target from a height of 2.40\,\text m2.40m2, point, 40, start text, m, end text. The drone is trave

ling horizontally at a speed of 1.50\,\dfrac{\text m}{\text s}1.50 s m ​ 1, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
Physics
2 answers:
Genrish500 [490]4 years ago
8 0

Answer:

1.05m

Explanation:

BaLLatris [955]4 years ago
3 0

Answer:

1.05m

Explanation:

To get this answer, you must first know how long it takes the ball to reach the ground. In order to figure that out, the process is simple:

First: Multiply the object's height by 2.

2.4x2=4.8

Next: Divide that answer by the speed of Gravity, 9.8 or 9.81m/s^2

(I prefer to use the method used by engineers, attend to precision, so I keep the same number of decimals in each number I am calculating.)

4.8/9.8=0.48979591836734693877551020408163m/s^2

Next: Square Root this answer.

=0.69985421222376517091350973563025

Last: Multiply your square rooted answer by your  forward velocity.

0.69985421222376517091350973563025x1.5=

1.0497813183356477563702646034454 or, since Khan Academy only wants three significant digits, round up to 1.05.

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Please answer all of these questions and you will get the brain list
pogonyaev

Answer:

1=900j

2=140j

3=5m

Explanation:

1,

work=force×displacement

w=450×2

w=900j

2,

w=f×s

w=70×2

w=140j

3,

w=f×s

200=40×s

200/40=s

s=5m

6 0
3 years ago
Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.
LiRa [457]

Answer:

         Time - taken = 2.5 s

          deceleration= -8 m/s²

Solution:

            Given:

                     speed, v = 8 m/s

                 distance, d = 20m

                     

              To Find:

                     deacceleration = ?

               

               As we know speed is defined as

                          v = d/t

                plugging in the values

                          t =  20/ 8

                          t = 2.5s

                Now from deceleration formula

                        a =  - v/ t

                        a = - 20/ 2.5

                        a = - 8 m/s²

          Thus, the time taken and acceleration is 2.5 s and -8 m/s²

          respectively.

          Learn more about deceleration here:

                brainly.com/question/13354629

                       #SPJ4  

               

                       

             

7 0
2 years ago
The Sun is to a planet as -
serg [7]

Answer:a

Explanation:

5 0
3 years ago
The root-mean-square speed (thermal speed) of the molecules of a gas is 200m/s at 23.0°C. At 227°C the root-mean-square speed (t
777dan777 [17]

Answer:

330 m/s  approx

Explanation:

The RMS speed of a gas is proportional to square root of its absolute temperature is

V ( RMS ) ∝ √T

\frac{V_1}{V_2} =\sqrt{\frac{T_1}{T_2} }

Here V₁ = 200 , T₁ = 23 +273 = 300K , T₂ = 227 +273 = 500 K

Putting the values

200 / V₂ = \sqrt{\frac{300}{500} }

V₂ = 330 m/s  approx

8 0
3 years ago
a 5.00 × 105 kg rocket is accelerating straight up. Its engines produce 1.50 × 107 of thrust, and air resistance is 4.50 × 106 N
Angelina_Jolie [31]
This one is simple :)

use the equation F = ma and then re-arrange for a.

a = F / m

But there is a trick, so be careful. the question gives you wind resistance. Simply subtract the wind resistance from the thrust of the rocket to get the net force upward.

1.50 * 10^7N - 4.5 8 10^6N = 1.05 * 10^7N

So,

a =  \frac{F}{m} =  \frac{1.05*10^7N}{5.00*10^5kg}
3 0
4 years ago
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