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konstantin123 [22]
4 years ago
5

A drone drops a package on a target from a height of 2.40\,\text m2.40m2, point, 40, start text, m, end text. The drone is trave

ling horizontally at a speed of 1.50\,\dfrac{\text m}{\text s}1.50 s m ​ 1, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
Physics
2 answers:
Genrish500 [490]4 years ago
8 0

Answer:

1.05m

Explanation:

BaLLatris [955]4 years ago
3 0

Answer:

1.05m

Explanation:

To get this answer, you must first know how long it takes the ball to reach the ground. In order to figure that out, the process is simple:

First: Multiply the object's height by 2.

2.4x2=4.8

Next: Divide that answer by the speed of Gravity, 9.8 or 9.81m/s^2

(I prefer to use the method used by engineers, attend to precision, so I keep the same number of decimals in each number I am calculating.)

4.8/9.8=0.48979591836734693877551020408163m/s^2

Next: Square Root this answer.

=0.69985421222376517091350973563025

Last: Multiply your square rooted answer by your  forward velocity.

0.69985421222376517091350973563025x1.5=

1.0497813183356477563702646034454 or, since Khan Academy only wants three significant digits, round up to 1.05.

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An object 2cm high is placed 3cm in front of a concave lens of focal length 2cm, find the magnification?​
Simora [160]

Answer:

0.4

Explanation:

A concave lens is a diverging lens, so it will always have a negative focal length. Image distance is always negative for a concave lens because it forms virtual images.

From the lens formula;

1/f = 1/u+ 1/v

- 1/2 = 1/3 - 1/v

1/v = 1/3 + 1/2

v= 6/5

v= 1.2 cm

Magnification = image distance/object distance

Magnification = 1.2cm/3cm

Magnification = 0.4

8 0
3 years ago
Gravity causes all falling objects to accelerate at a rate of 98 m/s2.<br> O True<br> O False
aleksandrvk [35]
It’s true the acceleration of falling objects on earth due to gravity is 98ms2
8 0
3 years ago
If the height is 10m, what is the potential energy? Asuming that the mass is 10
Ratling [72]

\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}

we know,

\boxed{potential \: energy = mgh}

So,

\longmapsto10 \times 9.8 \times 10

\longmapsto980 \: joules

6 0
3 years ago
A child bounces a 51 g superball on the sidewalk. The velocity change of the super bowl is from 22 m/s downward to 14 m/s upward
noname [10]

Answer:

F=1.02x10^{-3} N

Explanation:

From the exercise we know:

m=51g*\frac{1kg}{1000g}=0.051kg

v_{1}=-22m/s

v_{2}=14m/s

t_{2}-t_{1}=1800s

So, the average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}=\frac{(14-(-22))m/s}{1800s}=0.02m/s^2

The average force is:

F=m*a=(0.051kg)(0.02m/s^2)=1.02x10^{-3} N

8 0
3 years ago
An X-Ray machine delivers a radiation dose of 5mRem/hr. at 3ft from the machine. How far will the X-Ray technician have to move
kupik [55]

Answer:

4.7ft

Explanation:

Pls see attached file

8 0
3 years ago
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