Answer:
1.308 * 10^(-5) m
Explanation:
We apply the condition for a single slit experiment:
y = (λ * D) / a
Where y = half width of fringe
λ = wavelength of light
D = distance of slit from screen
a = width of slit
We need to find a, so we make a the subject of formula:
a = (λ * D) / y
From the question:
λ = 550 nm = 550 * 10^(-9) m
D = 0.63 m
y = 0.053 / 2 = 0.0265 m
Therefore:
a = (550 * 10^(-9) * 0.63) / 0.0265
a = 1.308 * 10^(-5) m
The width of the slit is 1.308 * 10^(-5) m
Hey Friends
The answer to this question would be C
Hope i helped
~Katie
Answer:
0.235 nC
Explanation:
Given:
= the magnitude of electric field = 
= the magnitude of electric force on each antenna = 
= The magnitude of charge on each antenna
Since the electric field is the electric force applied on a charged body of unit charge.

Hence, the value of q is 0.235 nC.
False not radioactive isotope will have a half-life