If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?
1 answer:
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For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:
From which we can rewrite the acceleration as
where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
From which we can rewrite the acceleration as
where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
Answer:
<h2>9,226,250 J</h2>Explanation:
The kinetic energy of an object can be found by using the formula
v is the velocity
m is the mass
From the question we have
We have the final answer as
<h3>9,226,250 J</h3>Hope this helps you