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luda_lava [24]
1 year ago
14

Determine the vector perpendicular to the plane of A= 31+ 6j - 2k and B=4i-j +3k

Physics
1 answer:
Sliva [168]1 year ago
5 0

The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k

Let r be the vector perpendicular to A and B,

r = A * B

A = 3i + 6j - 2k

B = 4i - j + 3k

a1 = 3

a2 = 6

a3 = - 2

b1 = 4

b2 = - 1

b3 = 3

a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k

a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k

a * b = 16 i - 17 j - 27 k

The perpendicular vector, r = 16 i - 17 j - 27 k

Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k

To know more about perpendicular vectors

brainly.com/question/14384780

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Answer:

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Explanation:

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3 years ago
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When particle enter in magnetic field at the angle of 90° so particle moves in circle

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By comparing above two equation,

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A satellite of mass m is in a circular orbit of radius R2 around a spherical planet of radius R1 made of a material with density
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They give us the density of the planet

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Part B

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3 years ago
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