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3 years ago

13

What's a broad flat volcano created by quiet eruptions

1 answer:

Evgesh-ka [11]3 years ago

4 0

A shield Volcano

The other, Larger Volcano with steeper sides is a composite volcano

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Why do<br> stars seem to move at night?<br> ght

Tema [17]

It looks that way cause the earth is rotation on its axis

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2 years ago

Read 2 more answers

A train travels 250 km westward from Carthage to Johnson City. The train arrives 2.5 hours after it left. What was the average v

den301095 [7]

The answer is C 100 km/h west

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3 years ago

Science Seminar Question: Why did Vehicle 2 fall off the cliff in Claire's test of the collision scene but Vehicle 2 did not fal

asambeis [7]

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because, $Weight_{vehicle 1} < Weight_{vehicle 2}$ but in Claire's test, vehicle 2 off the cliff because $Weight_{vehicle 1} \geq Weight_{vehicle 2}$

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff. In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

8 0

2 years ago

. Imagine that you are standing at the center of a giant bowl of gelatin. What type of wave will you make across the top of the

vichka [17]

Transverse wave as the wave is going up and down no compressions

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3 years ago

In the physics lab, a block of mass M slides down a frictionless incline from a height of 35cm. At the bottom of the incline it

bogdanovich [222]

Solution :

Given :

M = 0.35 kg

$m=\frac{M}{2}=0.175 \ kg$

Total mechanical energy = constant

or $K.E._{top}+P.E._{top} = K.E._{bottom}+P.E._{bottom}$

But $K.E._{top} = 0$ and $P.E._{bottom} = 0$

Therefore, potential energy at the top = kinetic energy at the bottom

$\Rightarrow mgh = \frac{1}{2}mv^2$

$\Rightarrow v = \sqrt{2gh}$

$=\sqrt{2 \times 9.8 \times 0.35}$ (h = 35 cm = 0.35 m)

= 2.62 m/s

It is the velocity of M just before collision of 'm' at the bottom.

We know that in elastic collision velocity after collision is given by :

$v_1=\frac{m_1-m_2}{m_1+m_2}v_1+ \frac{2m_2v_2}{m_1+m_2}$

here, $m_1=M, m_2 = m, v_1 = 2.62 m/s, v_2 = 0$

∴ $$v_1=\frac{0.35-0.175}{0.5250}+\frac{2 \times 0.175 \times 0}{0.525}$

$=\frac{0.175}{0.525}+0$

= 0.33 m/s

Therefore, velocity after the collision of mass M = 0.33 m/s

3 0

2 years ago