No...........................................................................Work for them urself
If a man has a mass of 83 kilograms on Earth, the force of gravity on his body be on the moon 135.6N. force =mass*acc , 83 * 9.8/6= 813.4/6 = 135.6N
Answer:
2856.96 J
0
0

6.78822 m/s
Explanation:
= Initial velocity = 9.6 m/s
g = Acceleration due to gravity = 9.81 m/s²
h = Height
The athlete only interacts with the gravitational potential energy. Air resistance is neglected.
At height y = 0
Kinetic energy

At height y = 0 the potential energy is 0 as

At maximum height her velocity becomes 0 so the kinetic energy becomes zero.
As the the potential and kinetic energy are conserved
The general equation

Half of maximum height



The velocity of the athlete at half the maximum height is 6.78822 m/s
From our perspective on Earth, two types of eclipses <span>occur: </span>lunar<span>, the blocking of the </span>Moon<span> by Earth's shadow, and </span>solar, the obstruction of the Sun by the Moon<span>. ... When Earth passes directly </span>between<span> Sun and </span>Moon<span>, its shadow creates a </span>lunar eclipse<span>.</span>
Answer:
60a in a circuit with a 12v battery
Explanation:
60a in a circuit with a 12v battery