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neonofarm [45]
1 year ago
11

give an example of one living and one non-living thing that uses the force of buoyancy to function. explain how they work.

Physics
2 answers:
zaharov [31]1 year ago
4 0

Answer:

the biotic one is a human in water and they flaot because of the air in our lungs and the abiotic one is a swimming buoys are filled with foam and foam floats

Explanation:

...

Ber [7]1 year ago
4 0
Some examples are a boat sailing on the river, Iceberg floating on water, A person with a life vest floating on water, Ship floating on the ocean, Helium balloon rising in the air. The buoyant force is proportional to the density.
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A solid wooden cube, 30cm on each side can be totally submerged in water if it is pushed downward with a force of 54N. What is t
Stels [109]

Answer:

the density of the wooden cube is 204.1 kg/m³

Explanation:

Given;

applied force, F = 54 N

length of each side of the solid wooden cube, L = 30 cm = 0.3 m

mass of the wooden cube is calculated as;

F = mg

m = F/g

m = 54/9.8

m = 5.51 kg

The volume of the wooden cube is calculated as;

V = L³

V = (0.3)³

V = 0.027 m³

The density of the wooden cube is calculated as;

ρ = m/V

ρ = (5.51 kg) / (0.027 m³)

ρ = 204.1 kg/m³

Therefore, the density of the wooden cube is 204.1 kg/m³

4 0
2 years ago
If a hammer has a resistance arm of 3 inches and the effort arm is 15 inches. What is the mechanical advantage?
Sunny_sXe [5.5K]

Answer:

Option D

MA=5

Explanation:

Mechanical advantage is the  the ratio of the output force to the  input force hence

MA=\frac {Effort arm length}{Load arm length}

Substituting 15 inches for the effort arm length and 3 inches for the load arm length then we obtain the mechanical advantage as

MA=\frac {15}{3}=5

4 0
3 years ago
A car traveling in a straight line at an initial speed of 8.0 meters per second accelerates uniformly to a speed of 14 meters pe
Whitepunk [10]

The equation we can use here is:

v^2 = v0^2 + 2 a d

where v is final velocity, v0 is intial velocity, a is acceleration and d is distance

 

14^2 = 8^2 + 2 a (44)

<span>a = 1.5 m/s^2</span>

4 0
2 years ago
Read 2 more answers
Did I do this right??
Nikitich [7]

Answer:

yes

Explanation:

good job

7 0
2 years ago
Two insulated copper wires of similar overall diameter have very different interiors. One wire possesses a solid core of copper,
Marrrta [24]

Answer:

a

 Solid Wire     I  =   0.01237 \  A      

  Stranded  Wire  I_2  =   0.00978 \  A

b

  Solid Wire   R  = 0.0149 \ \Omega

   Stranded  Wire  R_1  = 0.0189 \ \Omega

Explanation:

Considering the first question

From the question we are told that

  The  radius of the first wire is  r_1  = 1.53 mm = 0.0015 \  m

  The radius of  each strand is  r_0 =  0.306 \ mm =  0.000306 \ m

  The current density in both wires is  J  =  1750 \  A/m^2

Considering the first wire

     The  cross-sectional area of the first wire is

      A   = \pi  r^2

= >  A   = 3.142 *  (0.0015)^2

= >  A   = 7.0695 *10^{-6} \  m^2

Generally the current in the first wire is    

     I  =  J*A

=>  I  =  1750*7.0695 *10^{-6}

=>  I  =   0.01237 \  A

Considering the second wire  wire

The  cross-sectional area of the second wire is

     A_1  =  19 *  \pi r^2

=>     A_1  =  19 *3.142 *  (0.000306)^2

=>  A_1  =  5.5899 *10^{-6} \  m^2

Generally the current is  

      I_2  =  J  *  A_1

=>    I_2  =   1750  *  5.5899 *10^{-6}

=>    I_2  =   0.00978 \  A

Considering question two  

 From the question we are told that

     Resistivity is  \rho  =  1.69* 10^{-8} \Omega \cdot m

     The  length of each wire  is  l =  6.25 \  m

Generally the resistance of the first wire is mathematically represented as

    R  =  \frac{\rho *  l  }{A}

=> R  =  \frac{  1.69* 10^{-8} * 6.25 }{ 7.0695 *10^{-6} }

=> R  = 0.0149 \ \Omega

Generally the resistance of the first wire is mathematically represented as

    R_1  =  \frac{\rho *  l  }{A_1}

=> R_1  =  \frac{  1.69* 10^{-8} * 6.25 }{5.5899 *10^{-6} }

=> R_1  = 0.0189 \ \Omega

3 0
3 years ago
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