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3 years ago

If a sodium atom looses an electron to form an ion what is its charge?

Chemistry

2 answers:

Igoryamba3 years ago

7 0

Is there any answers to choose from?
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Goshia [24]3 years ago

5 0

wen a sodium atom loses an electron it will become a positive sodium ion NA+

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Use electron configurations to account for the stability of the lanthanide ions Ce⁴⁺ and Eu²⁺.

Citrus2011 [14]

Answer:

Explanation:

The Ce metal has electronic configuration as follows

[Xe] 4f¹5d¹6s²

After losing 4 electrons , it gains noble gas configuration ,. So Ce ⁺⁴ is stable.

Eu has electronic configuration as follows

[ Xe ] 4 f ⁷6s²

[ Xe ] 4 f ⁷

Its outermost orbit contains 2 electrons so Eu²⁺ is stable. Its +3 oxidation state is also stable.

Ce⁺²

7 0

3 years ago

Identify each example on the diagram as a carbon source or a carbon sink

cluponka [151]

You didn’t put a diagram up

5 0

3 years ago

What happens as you decrease the temperature of a solution?

ANTONII [103]

A). The number of solute particles increases

This was answered before on Brainly!
I used it for one of my chemistry courses before as well.

Hope this helps!

3 0

3 years ago

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What is the relationship between genes, chromosomes, and DNA? How are they organized inside of a cell?

Crazy boy [7]

They are combined 50% from your mom and the other from your dad

5 0

3 years ago

Calculate the fraction of lattice sites that are schottky defects for cesium chloride at its melting temperature (645oc). assume

baherus [9]

Answer : 7.87 X $10^{-6}$ .

Explanation : To find the fraction of schottky defects in the given lattice of CsCl,

we use the formula, $\frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )$

on solving with the given values , $Q_{s}= 1.86 eV$ and T as 645 + 273 K and rest are the constants.

$\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )$

we get the answer as 7.87 X $10^{-6}$ .

6 0

3 years ago

Read 2 more answers