Explanation:
When the covalent bonds in a molecule are polarized so that one portion of the molecule experiences a positive charge and the other portion of the molecule experiences a negative charge. This separation of opposite charges creates an electric dipole.
Answer:
electron: orbiting around the nucleus
proton: inside the nucleus
neutron: inside the nucleus
It’s the first one: A. the water molecules stay the same they just change phase to a gas
Answer:
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)
Explanation:
All the following are oxidation–reduction reactions except:________
a. H₂(g) + F₂(g) → 2HF(g). Redox. H is oxidized and F is reduced.
b. Ca(s) + H₂(g) → CaH₂(s). Redox. Ca is oxidized and H is reduced.
c. 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g). Redox. K is oxidized and H is reduced.
d. 6Li(s) + N₂(g) → 2Li₃N(s). Redox. Li is oxidized and N is reduced.
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g). Not redox. All the elements have the same oxidation number
When heat energy at a constant pressure = the change of enthalpy
ΔH = Q
and when the internal energy of an ideal gas formula is:
ΔH = n.Cp.ΔT
and when Cp = (5/2) R at a constant pressure of a monatomic ideal gas
∴Q = n.(5/2).R.ΔT
∴ ΔT = Q / [n.(5/2).R]
when Q is the heat required = 43.08 J (given)
and n is no.of moles = mass / molar mass
= 1.1 g / 39.948 g/mol
= 0.0275 moles
and R is gas constant = 8.314472J/mol K
by substitution:
ΔT = 43.08 J / (0.0275moles *(5/2) * 8.314472 J/mol K
= 76.76 K
