The bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.
No of moles of calcium bromide is calculated as follows:
moles = 1.642 ÷ 199.89 = 8.215 × 10-³moles
Molarity = 8.215 × 10-³moles ÷ 469.1mL = 1.75 × 10-⁵M
Therefore, the bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.
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Answer:
Hi
A conjugate acid is a chemical compound formed by the reception of a proton by a base; therefore, it is a base with an added hydrogen ion. On the other hand, a conjugate base is what remains after an acid has donated its proton during a chemical reaction, so it can be said that a conjugate base is a species modified by extracting a proton from an acid.
In pyrrole, the electron pair can be relocated to the ring and its availability is very small. In addition, the concept of aromaticity comes into play.
In the attached file are the schemas of the conjugate bases.
Explanation:
Answer:
The term "sustainable communities" has various definitions, but in essence refers to communities planned, built, or modified to promote sustainable living. Sustainable communities tend to focus on environmental and economic sustainability, urban infrastructure, social equity, and municipal government.
Answer:
4.47 x 10²² atoms
Explanation:
Given parameters:
Mass of Bismuth = 15.5g
Unknown:
Number of atoms = ?
Solution:
To find the number atoms, first solve for the number of moles in this element first.
Number of moles = 
Number of moles = 
= 0.074mole
So:
1 mole of a substance contains 6.02 x 10²³ atoms
0.074 mole of Bismuth will contain 0.074 x 6.02 x 10²³ atoms
= 4.47 x 10²² atoms
we are given
a swimming pool contains 2,850 kiloliters (kL) of water
2,850 kiloliters (kL)=2850000L
we know that
Firstly , we will find for 1L
now, we can multiply both sides by 2850000
so,
a swimming pool contains 752972.25892gal of water...........Answer
