How many moles of NaOH are present in 25.0 mL of a 0.1000 M NaOH solution?
2 answers:
the mole of NaOH = 2.5.10-5
<h3><em> Further Explanation</em></h3>The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
- Mole
Mole itself is the number of particles contained in a substance amounting to 6.02.10²³
Mole can also be sought if the amount of substance mass and its molar mass is known
mol = mass / molar mass
- Molarity (M)
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
<em> Known variables</em>
25.0 mL of a 0.1000 M NaOH solution
<em>Asked</em>
number of moles
<em>Answer </em>
We convert the volume unit, ml into Liter
because 1 liter = 1000 ml then
25 ml = 25.10⁻³ = 2.5.10⁻⁴ liters
then the mole of NaOH =
mol = concentration. volume
mol = 0.1. 2,5.10⁻⁴
mol = 2.5.10⁻⁵
<em>Learn more </em>
Calculate the molarity of a solution
Keywords: molarity, mole, volume, concentration, solution, NaOH ,
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Taking into account the reaction stoichiometry, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
3 Cu+ 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 3 moles
- HNO₃: 8 moles
- Cu(NO₃)₂: 3 mole
- NO: 2 moles
- H₂O: 4 moles
The molar mass of the compounds is:
- Cu: 63.55 g/mole
- HNO₃: 63 g/mole
- Cu(NO₃)₂: 187.55 g/mole
- NO: 30 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Cu: 3 moles ×63.55 g/mole= 190.65 grams
- HNO₃: 8 moles ×63 g/mole= 504 grams
- Cu(NO₃)₂: 3 moles ×187.55 g/mole= 562.65 grams
- NO: 2 moles ×30 g/mole= 60 grams
- H₂O: 4 moles ×18 g/mole= 72 grams
The following rule of three can be applied: if by reaction stoichiometry 504 grams of HNO₃ form 562.65 grams of Cu(NO₃)₂, 4.69 grams of HNO₃ form how much mass of Cu(NO₃)₂?
<u><em>mass of Cu(NO₃)₂= 5.2634 grams</em></u>
Then, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.
Learn more about the reaction stoichiometry:
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