How many moles of NaOH are present in 25.0 mL of a 0.1000 M NaOH solution?
2 answers:
the mole of NaOH = 2.5.10-5
<h3><em> Further Explanation</em></h3>The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
- Mole
Mole itself is the number of particles contained in a substance amounting to 6.02.10²³
Mole can also be sought if the amount of substance mass and its molar mass is known
mol = mass / molar mass
- Molarity (M)
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
<em> Known variables</em>
25.0 mL of a 0.1000 M NaOH solution
<em>Asked</em>
number of moles
<em>Answer </em>
We convert the volume unit, ml into Liter
because 1 liter = 1000 ml then
25 ml = 25.10⁻³ = 2.5.10⁻⁴ liters
then the mole of NaOH =
mol = concentration. volume
mol = 0.1. 2,5.10⁻⁴
mol = 2.5.10⁻⁵
<em>Learn more </em>
Calculate the molarity of a solution
Keywords: molarity, mole, volume, concentration, solution, NaOH ,
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Answer:
5.25 moles.
Explanation:
The decomposition reaction of NaN₃ is as follows :
We need to find how many grams of N₂ produced in the process.
From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.
2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,
3.5 moles of sodium azide decomposes to give moles of nitrogen gas.
Hence, the number of moles produced is 5.25 moles.