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3 years ago

How many moles of NaOH are present in 25.0 mL of a 0.1000 M NaOH solution?

Chemistry

2 answers:

Kisachek [45]3 years ago

4 0

25 * 10^-3 L * 0.1 Mole/L = 25*10^-4 Moles

Hope it helps.

Westkost [7]3 years ago

4 0

the mole of NaOH = 2.5.10-5

<h3> Further Explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mole

Mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

mol = mass / molar mass

Molarity (M)

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed{\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

 Known variables

25.0 mL of a 0.1000 M NaOH solution

Asked

number of moles

Answer 

We convert the volume unit, ml into Liter

because 1 liter = 1000 ml then

25 ml = 25.10⁻³ = 2.5.10⁻⁴ liters

then the mole of NaOH =

mol = concentration. volume

mol = 0.1. 2,5.10⁻⁴

mol = 2.5.10⁻⁵

Learn more 

Calculate the molarity of a solution

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Keywords: molarity, mole, volume, concentration, solution, NaOH ,

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