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valentina_108 [34]
3 years ago
5

At a skills competition, a target is being lifted into the air by a cable at a constant speed. An archer standing on the ground

launches an arrow toward the target. The system of equations below models the height, in feet, of the target and the arrow t seconds after it was fired. Which statement most likely describes the situation modeled by this system? mc016-1.jpg
Mathematics
1 answer:
adell [148]3 years ago
5 0
From the kinematic equations, s(t) = s_in + (v_in)(t) - (1/2)(g)(t^2). This means that there is an initial distance of 4, initial velocity and acceleration (in opposite direction of the motion) f 32. Option 4 shows the correct answer.
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3.) You are wrapping a present in shape of a tube,
Lapatulllka [165]
No. surface area is: 2x2x2xpi (2 circle ends) + 4x12xpi (long round outside) = 175.99 ft
5 0
3 years ago
Find the mean, median, and mode for the following scores: 8, 7, 5, 7, 0, 10, 2, 4, 11, 7, 8, 7
marusya05 [52]

Answer:

mode is 7, mean, 6.3 repeating, median 7

Step-by-step explanation:

4 0
3 years ago
Translate triangle p by vector 2 -7
NikAS [45]

Answer:  triangle p by vector 2 -7

ਵੈਕਟਰ 2 -7 ਦੁਆਰਾ ਤਿਕੋਣ ਪੀ

6 0
3 years ago
HELPPP!!!???PLEASE HELPPP!!
andriy [413]

Answer:

\frac{5}{14} or 0.357142857143

Step-by-step explanation:

__________________________________________________________

\frac{2}{7}\div\frac{4}{5} = \frac{5}{14} because,

\frac{2}{7} = 0.285714285714

\frac{4}{5} = 0.8

0.285714285714 \div 0.8 = 0.357142857143

\frac{5}{14} = 0.357142857143

__________________________________________________________

<em>Hope this helps! <3</em>

__________________________________________________________

8 0
3 years ago
Read 2 more answers
HELP PLEASE!!
Harman [31]

Answer:  \text{quadrilateral FSHB}\sim\text{quadrilateral KTWJ }

Step-by-step explanation:

To polygons are said to be similar if all the corresponding angles of given polygons are equal.

In the given figure, it can be seen that in quadrilateral FSHB and quadrilateral KTWJ all the corresponding angles are equal.

∠F=∠K

∠S=∠T

∠H=∠W

∠B=∠J

Therefore, The given polygons are similar.

Hence, \text{quadrilateral FSHB}\sim\text{quadrilateral KTWJ }

7 0
4 years ago
Read 2 more answers
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