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levacccp [35]
3 years ago
5

How does the distance from an eye chart affect the number of letters that are recognized on a line

Physics
2 answers:
luda_lava [24]3 years ago
8 0

Explanation:

Distance from the eye chart are used to find defect in the in the eye sights of a patient. If one cannot see far off things, that means he is near sighted. So if he goes away from the eye chart and try to see the letters in the chart, he will see blur image of the letters.

           And if one is far sighted he cannot see the near by things. If one comes closer to the chart and tries to read the letters then he will not be able to read those letters because he is far sighted.

Thus, in this way distance from the eye chart affect to recognize the letters present in the eye chart.

Nat2105 [25]3 years ago
3 0
Well, if you are nearsighted which means you can't see far, the father you are the more blurry it will be, resulting to you saying the wrong letter. This then shows the doctor that you can't see far away, nearsighted.
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What would happen to the brightness of the bulbs if the switch was opened​
jeka57 [31]
When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through. When only “bulb a” is connected to the battery then more current is flowing to “bulb a” causing it to be bright. So the light of “bulb a” will be dimmer.
6 0
3 years ago
a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the
m_a_m_a [10]

Answer:

2.846m

Explanation:

The diver is performing projectile motion.

To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)

x(initial) = 0

x(final) = ?

v(initial) = 2.3 m/s

we don't know t

To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)

- 9.8 in the acceleration in the y dir.

y(final) = 0

y(initial) = 7.5

v(initial in the y dir.) = 0

If we solve for t we get: t = 1.237s

Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)

x(final) = 2.3*1.237 + 0

x(final) = 2.846m

6 0
3 years ago
3.) What is the velocity of a 5.5 kg object that has a momentum of 550 kg-m/s?
stepladder [879]

Answer:

idk

Explanation:

8 0
3 years ago
A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine
bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

Power = \frac{Work done}{Time}

As Work done = Force acting on the machine × Displacement

So Power = \frac{(Force * Displacement)}{Time}

Power = \frac{(100*5)}{4}=125 W

So, 125 W is the power output of this machine.

6 0
3 years ago
The time required to produce one cycle of a wave is known as the waves
eimsori [14]
The time described above is known as the waves Period.
The time which it takes for a particle to complete one full cycle is known as the period. Period is normally measured in seconds. Frequency on the other hand is the number of cycles which are completed in a given period of time e.g a second. periodic time T is given by reciprocal of frequency (1/f).
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