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levacccp [35]
3 years ago
5

How does the distance from an eye chart affect the number of letters that are recognized on a line

Physics
2 answers:
luda_lava [24]3 years ago
8 0

Explanation:

Distance from the eye chart are used to find defect in the in the eye sights of a patient. If one cannot see far off things, that means he is near sighted. So if he goes away from the eye chart and try to see the letters in the chart, he will see blur image of the letters.

           And if one is far sighted he cannot see the near by things. If one comes closer to the chart and tries to read the letters then he will not be able to read those letters because he is far sighted.

Thus, in this way distance from the eye chart affect to recognize the letters present in the eye chart.

Nat2105 [25]3 years ago
3 0
Well, if you are nearsighted which means you can't see far, the father you are the more blurry it will be, resulting to you saying the wrong letter. This then shows the doctor that you can't see far away, nearsighted.
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Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 2.88 kg and rotate with
Tanya [424]

Answer:

(a) K_{small}=4839.3J

(b) K_{larger}=17406.4J

Explanation:

Given data

The angular velocity of two cylinders ω=257 rad/s

The mass of the two cylinders m=2.88 kg

The radius of small cylinder r₁=0.319 m

The radius of larger cylinder r₂=0.605 m

For Part (a)

The rotational kinetic energy of the cylinder is given by:

K=\frac{1}{2}Iw^2

Where I is rotational of inertia of solid cylinder about its central axis.

So

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2

Substitute the given values

So

K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J

For Part (b)

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2

Substitute the given values

K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J

8 0
3 years ago
Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is A. definitely les
pashok25 [27]

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is

D. the same.

As per the rule, the amount of current in devices connected in series is equal. here in the given situation , the wire is in series with the filament. that is the reason that the current in filament and wire is same.

hence the correct choice is D)

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Answer: "important and helpful" Show garret is paying close attention to her coach. Hope this help!

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When a laser shines on a screen after passing through two closely spaced slits, you see ___
Aleonysh [2.5K]

Answer:

diffraction

Explanation:

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003 (part 1 of 2) 10.0 points
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