Answer:
B.
Explanation:
A position-time graph is a graph of the position of an object against (versus) time. The slope of the line of a position-time graph is typically used to determine or calculate the velocity of an object.
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Uniform velocity can be defined as a situation in which a physical object or body travels equal distances in equal intervals of time along a fixed direction, regardless of how small the interval may be.
During uniform velocity, both the magnitude and direction of the physical object in motion do not change with respect to time. Also, an object in uniform velocity has zero tangential acceleration and its graph is a straight line parallel to the time axis.
Hence, a vehicle with a uniform velocity of 10 meters per seconds (m/s) is represented by Graph B.
Answer:
Acceleration,
Explanation:
Initial velocity of a particle in vector form, u = (-5i - 2j) m/s
Final velocity of particle in vector form, v = (-6i + 7j) m/s
Time taken, t = 8 seconds
We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :
or
Hence, the value of acceleration vector is solved.
Answer:
The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.
Explanation:
Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:
Dividing the second equation by the first one, we obtain:
And, since , then:
It means that the velocity at the bottom of the ramp is 1.81m/s.
We could use this data, plus any of the two initial equations, to determine the acceleration:
So the acceleration is 3.30m/s^2.