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3 years ago

0.22 L of pancake syrup has a mass of 33 g.

Physics

1 answer:

katrin2010 [14]3 years ago

6 0

Answer:

a. 150 g/L

b. 75 g

c. 120 mL

Explanation:

a. 33g/0.22L=150 g/L

b. 33g/0.22L=150 g/L

150 g/L*0.5L=75g

c. 0.22L/33g=0.006667L/g

0.006667L/g*18g=0.12L

0.12L*1000=120mL

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Which of the following is an example of a technological solution to water pollution in a local pond?

dexar [7]

Sure: ths is called protyping and lets yu get a sende fo the effeciveness tof the cahnge and the cost of the change.

A - just like the scientific principle syu what to know what other know or have learned. Example would it be silly to build a nuclear power de-salinatiztion plant when a dam in the mountains wuld dothe savme thng and perhaps have the advatage of using local labor and preveinting floods and givng of hydro eletic power. 

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3 years ago

A 90.0-kg man runs at a constant speed of 11.5 m/s. what is his kinetic energy?

harina [27]

The kinetic energy possessed by the man is 517.5 Joules.

Given the following data:

Mass = 90.0 kg

Velocity = 11.5 m/s.

To find the kinetic energy of the man:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

$K.E = \frac{1}{2} MV^2$

Where:

K.E is the kinetic energy.

M is the mass of an object.

V is the velocity of an object.

Substituting the given values, we have;

$K.E = \frac{1}{2}$ × $90$ × $11.5$

$K.E = 45$ × $11.5$

Kinetic energy = 517.5 Joules.

Therefore, the kinetic energy possessed by the man is 517.5 Joules.

8 0

3 years ago

Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as

Dmitriy789 [7]

Answer:

a) $v=5.6725\,m.s^{-1}$

b) $h= 1.6420\,m$

Explanation:

Given:

mass of the body, $M=20\,kg$

mass of the tyre, $m=10\,kg$

length of hanging of tyre, $l=3.5m$

distance run by the body, $d=10m$

acceleration of the body, $a=3.62m.s^{-2}$

(a)

Using the equation of motion :

$v^2=u^2+2a.d$ ..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

$u=0m.s^{-1}$

putting the values in eq. (1)

$v^2=0^2+2\times 3.62 \times 10$

$v=8.5088\,m.s^{-1}$

Now, the momentum of the body just before the jump onto the tyre will be:

$p=M.v$

$p=20\times 8.5088$

$p=170.1764\,kg.m.s^{-1}$

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

$(M+m)\times v'=p$

$(20+10)\times v'=170.1764$

$v'=5.6725\,m.s^{-1}$

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

$\frac{1}{2} (M+m).v'^2=(M+m).g.h$

$\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h$

$h\approx 1.6420\,m$

above the normal hanging position.

3 0

3 years ago

Calculate the focal length of the mirror formed by the convex side of a shiny spoon that has a 1.54 cm radius of curvature. (b)

blondinia [14]

Explanation:

It is given that,

Radius of curvature of the mirror, R = 1.54 cm

(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

$R=2f$

f = focal length of the mirror

$f=\dfrac{1.54\ cm}{2}$

f = 0.77 cm

(b) The power of mirror is given by the reciprocal of focal length i.e.

Power, $P=\dfrac{1}{f}$

P = 1.29 diopters

Hence, this is the required solution.

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4 years ago

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?

iris [78.8K]

Answer:

Explanation:

The equation for acceleration is

$a=\frac{v_f-v_0}{t}$ where vf is the final velocity and v0 is the initial velocity. For us, the final velocity is 25 m/s and the initial is 0 because the train started from resting position. Filling in and solving for a:

$a=\frac{25-0}{30.0}$ so

a = .83 m/s/s

4 0

3 years ago