Saying no and not throwing fits and manners.
<span>The blades should turn in two directions.</span>
Answer:
The minimum wall thickness Tmin required for the spherical tank is 65.90mm
Explanation:
Solution
Recall that,
Tmin = The minimum wall thickness =PD/2бp
where D = diameter of 8.0 m
Internal pressure = 1.62 MPa
Then
The yield strength = 295MPa/3.0 = 98.33
thus,
PD/2бp = 1.62 * 8000/ 2 *98.33
= 12960/196.66 = 65.90
Therefore the wall thickness Tmin required for the spherical tank is 65.90mm
Answer :
New force becomes, F' = 1.83 N
Explanation:
Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :
![F=\dfrac{kq_1q_2}{r^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Br%5E2%7D)
are charges
r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r
New force is given by :
![F'=\dfrac{kq^2}{r'^2}](https://tex.z-dn.net/?f=F%27%3D%5Cdfrac%7Bkq%5E2%7D%7Br%27%5E2%7D)
![F'=\dfrac{kq^2}{(2r)^2}](https://tex.z-dn.net/?f=F%27%3D%5Cdfrac%7Bkq%5E2%7D%7B%282r%29%5E2%7D)
![F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}](https://tex.z-dn.net/?f=F%27%3D%5Cdfrac%7B1%7D%7B4%7D%5Cdfrac%7Bkq%5E2%7D%7Br%5E2%7D)
![F'=\dfrac{1}{4}\times 7.35](https://tex.z-dn.net/?f=F%27%3D%5Cdfrac%7B1%7D%7B4%7D%5Ctimes%207.35)
F' = 1.83 N
So, the new force between charges will be 1.83 N. Therefore, this is the required solution.