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3 years ago

A transparent film laminated to a fabric is identified in the study material as

1 answer:

8 0

The transparent film laminated to a fabric is identified in the study material as PVC. PVC or polyvinyl chloride is a type of synthetic resin. For fabric, PVC on fabric is typically plastic-coated polyester, and is more resistant to wear and tear than others.

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When you eat a candy bar, your body oxidizes glucose to get energy. where does this energy come from? kinetic energy of the gluc

babymother [125]

The correct answer is
"chemical bonds within the glucose molecules "

The chemical bonds of the glucose molecules contain chemical energy, and when these bonds are broken by the processes acting inside the body, the energy of the bonds is released and it can be used by the body.

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3 years ago

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 17 feet. The ball is started in moti

Romashka-Z-Leto [24]

twelve because it is the answer

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3 years ago

Read 2 more answers

HELP!!!

natta225 [31]

Answer:

energy of position

Explanation:

I think that is the answer

6 0

3 years ago

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the

leonid [27]

Answer:

$KE_A=33\ J$

$KE_B=99\ J$

Explanation:

Given:

Let mass of the particle B be, $m_B=m$

then the mass of particle A, $m_A=3m$

Energy stored in the compressed spring, $E=132\ J$

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

$\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132$

$3m.v_A^2+m.v_B^2=264$ .............................(1)

Using the conservation of linear momentum:

$m_A.v_A+m_B.v_B=0$

$3m.v_A+m.v_B=0$ .............................(2)

Put the value of $v_A$ from eq. (2) into eq. (1)

$3m\times (\frac{-v_B}{3})^2+m.v_B^2=264$

$v_B^2=\frac{198}{m}$ ...........................(3)

Now the kinetic energy of particle B:

$KE_B=\frac{1}{2}\times m_B\times v_B^2$

$KE_B=\frac{1}{2}\times m\times \frac{198}{m}$

$KE_B=99\ J$

Put the value of $v_B^2$ form eq. (3) into eq. (1):

$v_A^2=\frac{22}{m}$

Now the kinetic energy of particle A:

$KE_A=\frac{1}{2}m_A.v_A^2$

$KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}$

$KE_A=33\ J$

6 0

3 years ago

WHICH SIGNAL IS TRANSFERRED IN ELECTRICAL WIRE ?

Dvinal [7]

Answer:

electrical signal is transferred in electrical wire

Explanation:

electrical signals are transmitted between segments of the axon by successive opening of channels down the atonal membrane with negative and positive charge fluxing on either side of the membrane through selectively permeable chlorine , sodium or potassium channels.

hope this ans may help you.

thankyou

Mrk me brainilist

8 0

3 years ago