The acceptable measurement of the length of the piece of paper is 3.5 cm.
<h3>What is measuring accuracy of a ruler?</h3>
The measuring accuracy of ruler determines how precise or accurate the length of an object is measured.
The limit of accuracy of a ruler is indicated by how "precisely" you can read the length on that ruler's scale—that is, how well you can estimate between the marks.
In a ruler the distance between the closest marks is 0.1 cm.
This implies that the measuring accuracy of meter rule is 0.1 cm.
The acceptable measurement of the length of the piece of paper is calculated as follows;
length = (3 cm + 4 cm)/2 = 3.5 cm
Thus, the acceptable measurement of the length of the piece of paper is 3.5 cm.
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Answer:
Carbon
Explanation:
If we keep many type of gas with carbon It will be mixture of Gases
P = 11.133 atm (purple)
T = -236.733 °C(yellow)
n = 0.174 mol(red)
<h3>Further explanation </h3>
Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:
- Boyle's law at constant T, P = 1 / V
- Charles's law, at constant P, V = T
- Avogadro's law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
In general, the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
To choose the formula used, we refer to the data provided
Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT
T= 10 +273.15 = 373.15 K
V=5.5 L
n=2 mol
V=8.3 L
P=1.8 atm
n=5 mol
T = 12 + 273.15 = 285.15 K
V=3.4 L
P=1.2 atm
A. As you make more and more of one good or service, you will also make more and more of another.
Answer:
24g of NaOH are required
Explanation:
Molarity, M, is an unit of concentration widely used in chemistry defined as the ratio between moles of solute (In this case, NaOH), and volume of solution in liters.
We can find the moles of NaOH and its mass with the volume and desired concentration as follows:
<em>Moles NaOH:</em>
400.0mL = 0.400L * (1.50mol / L) = 0.600 moles NaOH
<em>Mass NaOH -Molar mass: 40.0g/mol-:</em>
0.600 moles * (40.0g / mol) =
<h3>24g of NaOH are required</h3>