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mart [117]
3 years ago
6

Pure substance uniform

Chemistry
1 answer:
Lerok [7]3 years ago
6 0
What? there isn’t a question here
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A gas is at an original pressure of 412 torr and a temperature of 79°C. What is the new temperature of the gas (in K) if the pre
olga_2 [115]

Answer:

Whenever you are doing calculations with gases and temperature, you must convert the temperature from C into Kelvin. Then, just plug in your values and do the calculation. So, for the first one,

32C + 273 = 305 K

63C + 273 = 336 K

Then, P1/T1 = P2/T2

575 torr / 305 K = P2 / 336 K

P2 = 633 torr

For the second one:

P1/T1 = P2/T2

575/305 = 5750 / T2

T2 = 3050 K

7 0
3 years ago
Who was the first U.S. secretary of state to ever visit the remote cook islands in the south pacific
pogonyaev

Answer:

I think it was Hillary Clinton.

Explanation:

6 0
3 years ago
How did scientists find out about atoms before technology?
sasho [114]

Answer:

There are three ways that scientists have proved that these sub-atomic particles exist. They are direct observation, indirect observation or inferred presence and predictions from theory or conjecture. Scientists in the 1800's were able to infer a lot about the sub-atomic world from chemistry.

Explanation:

Hope this helps

6 0
3 years ago
PLEASE HELP 100!!!!! POINTS
insens350 [35]

i will ans the 2nd part first:


heat sources 4 homes: those wuld be renewable resources that generate heat. They include geothermal, solar water-heating and bio-mass.


primarily produce electricity: those wuld be something that is big like a dam for hydroelectric, wind turbine for electric generation, and solar farm for electricity.


4 0
4 years ago
Read 2 more answers
Suppose that 0.48 g of water at 25∘C∘C condenses on the surface of a 55-gg block of aluminum that is initially at 25∘C∘C. If the
GarryVolchara [31]

Answer : The final temperature of the metal block is, 25^oC

Explanation :

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of aluminum = 55 g

m_2 = mass of water = 0.48 g

T_{final} = final temperature = ?

T_1 = temperature of aluminum = 25^oC

T_2 = temperature of water = 25^oC

c_1 = specific heat of aluminum = 0.900J/g^oC

c_2 = specific heat of water= 4.184J/g^oC

Now put all the given values in equation (1), we get

55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]

T_{final}=25^oC

Thus, the final temperature of the metal block is, 25^oC

6 0
3 years ago
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