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ivanzaharov [21]
3 years ago
7

What is the current temperature to the nearest degree for the thermometer shown below?

Chemistry
2 answers:
kicyunya [14]3 years ago
6 0

Answer: -2

Explanation:

For the lad on edg

padilas [110]3 years ago
3 0
There is no temperature at all shown below. Is that the same as Absolute Zero ?
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Answer all of dem Free BRAINIEST ON THE ROLL
ycow [4]
T, F, T, T, F



Explain:


4 0
3 years ago
True or False. A force is a push or pull exerted on an object.
drek231 [11]

Answer:

TRUE

Explanation:

remember newtons laws of motion. Every action has an equal and opposite reaction. LOL

4 0
3 years ago
Read 2 more answers
Calculate the number of moles of each compound, given the number of molecules.
brilliants [131]

Answer:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

Explanation:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

5 0
3 years ago
A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott
Kipish [7]

Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

Given:

Mass = 14.0 g

Density (\rho) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}

Substituting value of m & density in the formula:

\sf \implies 1.38 =  \frac{14.0}{V} \\  \\   \sf \implies V =  \frac{14.0}{1.38} \\  \\   \sf \implies V = 10.14 \ cm^3

\therefore

Volume of the plastic used to make water bottle = 10.14 cm³

6 0
3 years ago
You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p
Elenna [48]

Answer:

  • <u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

  • PV=nRT

Where:

  • P = pressure = 1.25 atm
  • V = volume = 25.2 liter
  • R = Universal constant of gases = 0.08206 atm-liter/K-mol
  • T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
  • n = number of moles

Solving for n:

  • n=\frac{PV}{RT}

Substituting:

n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol

8 0
3 years ago
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