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2 years ago

What is the current temperature to the nearest degree for the thermometer shown below?

Chemistry

2 answers:

kicyunya [14]2 years ago

6 0

Answer: -2

Explanation:

For the lad on edg

padilas [110]2 years ago

3 0

There is no temperature at all shown below. Is that the same as Absolute Zero ?

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Synthesize Information In a multistep process, cells can combine the reactants glucose (C6H12O6) and oxygen (O2) to form the pro

zloy xaker [14]

Answer:

Explanation:

In one of the process, energy is built up from scratch, in the other one, energy is liberated for use by an organism or body.

The first process deals with a metabolic reaction in which energy is liberated:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy

In the above process, energy is liberated when glucose combines with oxygen. The waste products are carbon dioxide and water. This process liberates heat energy which can be used to do work.

In the reverse process:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

This process stores energy in carbon chains as chemical energy. It is this energy that is released in the first process.

Therefore, we can see that the first process liberates energy and the reverse process stores energy.

8 0

2 years ago

An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams

tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0

2 years ago

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energ

SSSSS [86.1K]

Answer: The molecules of oxygen gas that will be reduced to water are 42 molecules

Explanation:

We are given:

$E^o_{(NO_2^-/NH_4)}=-0.41V\\E^o_{(O_2/H_2O)}=0.82V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, oxygen will undergo reduction reaction will get reduced.

$NH_4$ will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

The half reactions follows:

Oxidation half reaction: $NH_4\rightarrow NO_2^-+6e^-$ ( × 4)

Reduction half reaction: $O_2+4e^-\rightarrow 2H_2O$ ( × 6)

Overall reaction: $4NH_4+6O_2\rightarrow 4NO_2^-+12H_2O$

We are given:

Molecules of $NH_4$ = 28

By Stoichiometry of the reaction:

4 molecules of $NH_4$ reacts with 6 molecules of oxygen gas

So, 28 molecules of $NH_4$ will react with = $\frac{6}{4}\times 28=42$ molecules of oxygen gas

Hence, the molecules of oxygen gas that will be reduced to water are 42 molecules

4 0

3 years ago

Both the oxygen you need to breathe and ozone are gases made only of oxygen. So why can't you survive by breathing ozone?

marshall27 [118]

Answer/Explanation: Two atoms of oxygen form the basic oxygen molecule--the oxygen we breathe that is essential to life. The third oxygen atom can detach from the ozone molecule, and re-attach to molecules of other substances, thereby altering their chemical composition.

8 0

2 years ago

1. Use the following equation:

fenix001 [56]

Answer:

7.28 mol

Explanation:

2 NaOH + H₂SO₄ = 2 H₂O + Na₂SO₄ -------------------(1)

mole fraction for the reaction is;

2 : 1 = 2 : 1

Number of moles of H₂SO₄ = 7.28 mol

1 mol of H₂SO₄ shall form 1 mole of Na₂SO₄

therefore,

7.28 mol of H₂SO₄ shall form 7.28 mole of Na₂SO₄

8 0

2 years ago

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