Answer:
47.5 mL
Solving:
M1 = 4.00 M
V1 = ?
M2 = 0.760 M
V2 = 0.250 L
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M1 * V1 = M2 * V2
V1 = ( M2 * V2 ) / M1
V1 = ( 0.760 * 0.250 ) / 4.00
V1 = ( 0.190 ) / 4.00
V1 = 0.0475 L
Heat required to raise the temperature = 159.505 J
<h3>Further explanation</h3>
Given
c = specific heat of Beryllium = 1.825 J/g C
m = mass = 2.3 g
Δt = Temperature difference : 60 - 22 = 38 °C
Required
Heat required
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
Q = 2.3 x 1.825 x 38
Q = 159.505 J
Answer:
MECHANISM:
1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.
2) Formation of carbocation.
3) Attack of Nucleophile Br − .
Explanation:
problem identification
hypothesis
experimentation
data collection and analysis
data interpretation
data presentation
conclusion
