The table with the data is in the picture attached.
Answer:
Explanation:
The reaction equation suggests that the law could have this form:
Then, the work is to find the values of the exponents that satisfy the initial rate data.
A first glance shows that for the third and fourth trials the initial rates are the same. Since for these two trials only the initial concentration of substance B changed (A and C were kept equal), you conclude that the reaction rate does not depend on B, and ist exponent (lower b) is 0.
Then, so far you can say:
When you use trials 1 and 2, you get:
Now, you can use trials 1 and 3 to determine the other exponent:
Thus, you have the rate law:
Now, you just use any trial to obtain k. Using trail 1:
Which yields:
Dalton was the first scientist to create an atomic theory but he wasn't given any credit. J.J Thompson was credited for his theory (apple pudding)
Answer:The hybridisation of C1 and C2 are sp3 and sp2 respectively.
Explanation:
Here the first carbon (C-1) formed four straight single bonds.
Linking to the electron theory (a fig.1 shown below) one electron from 2s orbital moves to the empty 2pz orbital.
The 2s and the three 2p orbitals hybridise and each orbital will be completed by one electron shared mutually with and from N, H, H, and the other C.
C-2 the second carbon has an sp2 because it forms a double bond with oxygen.
In the sp2 hybridisation the 2s orbital hybridises with only two 2p orbitals leaving the other 2p orbital unhybridised. The orbitals in sp2 is to be completed with one more electron each by sharing covalently with the C, O and the other O.
Note: The unhybridised p orbital is completed with the other shared electron of the oxygen. This forms the π bond in the carbon-oxygen double bond. (Fig 2. Shows the electronic arrangements.)
Boiling-point<span> elevation describes the phenomenon that the </span>boiling point<span> of a liquid (a </span>solvent<span>) will be higher when another compound is added, meaning that a </span>solution has<span> a higher </span>boiling point<span> than </span>a pure solvent<span>. This happens whenever a non-volatile solute, such as a salt, is added to </span>a pure solvent<span>, such as water.
So the correct answer is C.</span>